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Mice21 [21]
3 years ago
15

The buildup of plaque on the walls of an artery may decrease its diameter from 1.1 cm to 0.90 cm. The speed of blood flow was 17

cm/s before reaching the region of plaque buildup.
A). Find the speed of blood flow within the plaque region. This was 25 cm/s.
B.) Find the pressure drop within the plaque region. I got 17.808 but says I'm wrong. Am I missing a step?
Physics
1 answer:
natka813 [3]3 years ago
6 0

Answer

Initial radius of the artery is (1.1 cm) / 2 = 0.55 cm

final radius of the artery is (0.90 cm) / 2 = 0.45 cm

initial velocity of the blood is 17 cm/s

Using  equation of continuity is

                                      A₁v₁=A₂v₂

                                 π r₁² x v₁ = π r₂² x v₂

                                  r₁² x v₁ = r₂² x v₂

                                  0.55² x 17 =0.45² x v₂

                                        v₂=25.39 cm/s

Bernoulli's equation is

P_1 - P_2 = \dfrac{1}{2}\rho (v_2^2-v_1^2)

rho is the density of blood = 1060 kg/m^3

P_1 - P_2 = \dfrac{1}{2}\times 1060 \times (0.254^2-0.17^2)

P_1 - P_2 =18.87\ Pa

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