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3 years ago

In the Earth's mantle, heat is transferred in large convection currents. Within these currents,

Physics

2 answers:

chubhunter [2.5K]3 years ago

7 0

The answer is B. The hotter rock is less dense so rises. The cooler rock is more dense so sinks.

sertanlavr [38]3 years ago

4 0

B.) Hotter rock rises cooler rock sinks

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Identify and sketch all the external forces acting on the chair. Because the chair can be represented as a point particle of mas

Monica [59]

Answer:

y axis normal (N) and the weight (W)

x axis pplied force (F) and friction force (fr)

Explanation:

If we have a chair on a horizontal surface, the normal (N) and the weight (W) of the body act on the vertical axis.

On the x axis, the applied force (F) acts in the direction of movement and the friction force (fr) in the opposite direction of movement.

In this exercise we assume that the body tends to move to the right, all the forces can be seen in the adjoint

5 0

2 years ago

Remember to identify all your data, write the equation, and show your work.

Paraphin [41]

Answer:

I believe it's 8.09 seconds, but I'm rusty on my physics.

Explanation:

The equation for solving the time it takes for an object to fall is $\sqrt{2d/g}$

So multiply the distance times 2, and you get 642 meters. Then you divide by gravities acceleration constant, 9.8, and you get 65.51. Finally, $\sqrt{65.51}$ , and you get 8.09 seconds.

I pulled the equation off of wikipedia and I'm unsure if it's the correct one, so hopefully this is correct. :/

6 0

3 years ago

A rock at rest falls off a tall cliff and hits the valley below after 3.5s. What is the rocks velocity as it hits the ground

pogonyaev

T = 3.5 secs

Velocity (v) = g * t = 10 m/s^2 * 3.5 sec = 35 m/s

7 0

3 years ago

Read 2 more answers

The depth of the Pacific Ocean in the Mariana Trench is 36,198 ft. What is the gauge pressure at this depth

FinnZ [79.3K]

Answer:

the pressure at the depth is 1.08 × $10^{8}$ Pa

Explanation:

The pressure at the depth is given by,

P = h $\rho$ g

Where, P = pressure at the depth

h = depth of the Pacific Ocean in the Mariana Trench = 36,198 ft = 11033.15 meter

$\rho$ = density of water = 1000 $\frac{kg}{m^{3} }$

g = acceleration due to gravity ≈ 9.8 $\frac{m}{s^{2} }$

P = 11033.15 × 9.8 × 1000

P = 1.08 × $10^{8}$ Pa

Thus, the pressure at the depth is 1.08 × $10^{8}$ Pa

4 0

3 years ago

An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)

Alecsey [184]

"60 kg" is not a weight. It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is

   (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

   Weight = (60 kg) x (9.8 m/s²)

      =    588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is

(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

   (0.04) x (588 Newtons) = 23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.

6 0

3 years ago