All categories

4 years ago

What method has detected the most extrasolar planets so far?

Physics

1 answer:

Sedaia [141]4 years ago

5 0

<h2>Answer: The Transit method</h2>

Detecting extrasolar planets by direct observation (with a telescope) is a complicated task. This is because any planet constitutes an extremely dim light source compared to the star around which it orbits.

So, to detect this extremely dim source is quite difficult due to the glare of the star's light that dulls it.

In this sense, scientists and astronomers have made several methods to find these extrasolar planets, among which the most successful has been the transit method.

This method is based on <u>astronomical transit</u>, a phenomenon in which a body (a planet in this case) passes in front of a larger one (the star), blocking (eclipsing) its vision to some extent.

It should be noted that this is the method currently used in the search for extrasolar planets. Space agencies such as ESA (Europe) and NASA (USA) have put into orbit satellites with extremely sensitive photometric sensors to observe even the smallest variations of intensity of a star due to the passage of a planet.

You might be interested in

Answer needed asap............

NikAS [45]

I): Speed=Distance/Time
=65-30 km/12:30-12:00 hrs
=35 km/00:30hrs
=3500 m/1800 s
=1.94m/s

ii): Average Speed=Total Distance/Total Time
=100000 m/7200 s
=13.88 m/s

iii):No because it has different speeds at
different time intervals

5 0

3 years ago

Read 2 more answers

Question 11 (3 points)

kykrilka [37]

Answer:

С. 10.41 Ampere

Explanation:

Given that,

Power, P = 125 watts

Voltage, V = 12 volts

We need to find current. Power in terms of current and voltage is given by :

P = VI, I = current

$I=\dfrac{P}{V}\\\\I=\dfrac{125\ W}{12\ V}\\\\I=10.41\ A$

So, the current is 10.41 A.

5 0

3 years ago

an rlc series circuit has a 40.0 resistor,a 3.00 mH inductor, and a 5.00 capacitor, (a find the circuits impendance at 60.0 Hz

Gelneren [198K]

Answer:

Z = 530.89 ohms

Explanation:

Given that,

Resistor, R = 40 ohms

Inductor, L = 3 mH

Capacitor, C = 5 μF

We need to find the impedance of the circuit at frequency of 60 Hz. For a series LCR circuit, its impedance is given by the formula as follows :

$Z=\sqrt{R^2+(X_L-X_c)^2} \\\\Z=\sqrt{R^2+(2\pi fL-\dfrac{1}{2\pi fC})^2} \\\\Z=\sqrt{(40)^2+(2\pi \times 60\times 3\times 10^{-3}-\dfrac{1}{2\pi \times 60\times 5\times 10^{-6}})^2} \\Z=530.89\ \Omega$

So, the impedance of the circuit is 530.89 ohms.

7 0

4 years ago

An atom contains 15 neutrons and has a mass number of 30. What is its atomic number? How did you determine the atomic number?

irinina [24]

Answer:

Explanation:

The mass number is defined as the total number of protons and neutrons. The atomic number is total number of protons. And since we have the mass number and number of neutrons, we can use simple subtraction (30 - 15) to find that the atomic number is 15.

8 0

4 years ago

The radius of the circle traced out by the second hand on a clock is 6.00 cm. In a time t the tip of the second hand moves throu

quester [9]

Answer:

30.29 s

Explanation:

We are given that

Radius=r=6 cm

Length of an arc=l=19 cm

We have to find the value of t in seconds.

$\theta=\frac{l}{r}$