Answer:
Work done, W = 0.0219 J
Explanation:
Given that,
Force constant of the spring, k = 290 N/m
Compression in the spring, x = 12.3 mm = 0.0123 m
We need to find the work done to compress a spring. The work done in this way is given by :
W = 0.0219 J
So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.
Answer:
a = 0.77 m/s^2
Explanation:
The centripetal acceleration is given as
The velocity of the car can be calculated using the circumference of the track and the period of the car.
So, the acceleration is
Answer:
Explanation:
a ) maximum friction possible
= .3 x 30 x 9.8
= 88.2 N
It is friction force which creates acceleration in 30 kg packing case.
Friction force F
F = ma
= 30 x 2.51
= 75.3 N
It will be in north direction , the direction of acceleration.
b ) F = ma
= 30 x 3.63
= 108.9 N
But maximum friction force is 75.3 N , so load will start slipping northward. so friction force will be acting southward.
Friction force = .2 x 30 x 9.8 ( coefficient of kinetic friction applies )
= 58.8 N
towards south .
