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sesenic [268]
3 years ago
15

Kiran lit a candle she placed a 100cm (cubed) glass jar over the candle. The candle flame went out after 2 seconds. Why did the

flame go out?
Biology
1 answer:
larisa86 [58]3 years ago
6 0
The flame cannot be in a cubed jar long it has to be in a cylinder in order for the flame to stay lit. I hope this helps!
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Is the Great Green Wall an example of Secondary Succession?
shusha [124]

Answer:

The Great Green Wall is taking root in Africa's Sahel region, at the southern edge of the Sahara desert. The Great Green Wall is a symbol of hope in the face of one of the biggest challenges of our time - desertification. This game changing African-led initiative aims to restore Africa's degraded landscapes and transform millions of lives in one of the world's poorest regions, the Sahel.

Primary succession occurs on land where no previous growth has taken place and there is no substrate/soil. Secondary succession occurs on land where there has been previous growth, the soil and seed bank makes up the substrate.

Explanation:

I majored in Biology

7 0
3 years ago
Alcoholic fermentation
Gala2k [10]

A) Forms fewer ATP molecules than cellular respiration.  

It usually forms 2ATP as opposed to 38ATP formed during cellular respiration.

8 0
3 years ago
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If earth tides decreased what would be the most likely explanation?
WINSTONCH [101]
<span>If the earth tides are decreased, the explanation would likely be: the gravitational attraction decreases as the earth moved farther from the sun, thus, affecting the tide. On the other hand, if the gravitational pull increases, it would mean that the earth tide would also increase. Remember, the two major factors that influences earth tides are: gravitational pull of the moon and of course, the sun.</span>
8 0
4 years ago
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Organisms become extinct for many reasons. All BUT one is reason for extinction. That is
igomit [66]

Answer:

A) Adaptations

Explanation:

If a species learns to adapt to their environment, then they will not become extinct

5 0
3 years ago
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The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man
IgorLugansk [536]

Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

The length of  linker DNA in mammals is equal to 50 bp

Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

= 146 + 50\\= 196bp

Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

8 0
3 years ago
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