A: 38.4 - 25 = 13.4
13.4 + 32.65 = $46.05
B: 50.15 - 32.65 = 17.5
17.5 + 25 = 42.5 mph
Answer:
60-9pi if you need that rounded then 31.73
Step-by-step explanation:
10*6= 60
the two semi circles make one full circle. a circle formula is pi*r^2 = pi*3^2= 9pi
then subtract 9pi from 60
60-9pi = 31.73
These are two separate problems: in the first we will have to substitute in a new value for x into the original equation and in the second we will manipulate the preexisting equation for f(x).
To begin, we will sub in f(x/3). To do this, we will substitute each variable x in the equation (in this case there is only one) with x/3, and then simplify the resulting equation.
f(x) = 6x - 18
f(x/3) = 6(x/3) - 18
To simplify, we should distribute the 6 on the right side of the equation.
f(x/3) = 6x/3 - 18
Now, we can divide the first term on the right side to finalize our simplification.
f(x/3) = 2x -18
Secondly, we are asked to find f(x)/3. To do this, we will take our original value for f(x), and then simplify divide that entire function by 3.
f(x) = 6x - 18
f(x)/3 = (6x-18)/3
This means that we must divide each term of the binomial by 3, so we are really computing
f(x)/3 = 6x/3 - 18/3
We can simplify by dividing both of the terms.
f(x)/3 = 2x - 6
Therefore, your answer is that f(x/3) = 2x - 18, but f(x)/3 = 2x - 6. It is important to recognize that these are two similar, yet different, answers.
Hope this helps!
Answer:
Corn was planted in 24 sq.ft. of the vegetable garden.
Step-by-step explanation:
Length of garden = 9 ft
width of garden = 8 ft
Hence we will first find the total area of garden.
Total area of garden = length × width = 
He planted 1/2 of the garden with vegetables.
Hence.
Area of Vegetables garden = 
He planted tomatoes in 1/3 of the vegetable garden and corn in the rest
Area in which tomatoes was planted = 
Hence Area in which corn were planted = Area of Vegetables garden - Area in which tomatoes was planted = 
Hence Area of vegetable garden in which corn was planted is 24 sq.ft.
<span>When you add fractions, the denominators must be the same, so you may have to generate equivalent fractions by using the lowest common multiple of all the denominators. For subtraction of fractions, you use the same method. When multiplying fractions, you can only multiply the numerators together, and the denominators together. </span>
