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kondaur [170]
3 years ago
14

When Sally went bowling, her scores were 108, 72, and 95. If she bowls a 4th game, what will her score need to be to give her an

average of 91?
Mathematics
2 answers:
tekilochka [14]3 years ago
8 0

Answer:

The answer is 89.

Step-by-step explanation:

In order to determine the score that she needs, we have to know about the mean. The <em>mean </em>is the average that we use frequently, where we add up all the numbers and then divide by the amount of numbers.

We have to make a equation where let be x the fourth score. Then:

First score=108

Second score=72

Third score=95

Fourth score=x

Average (mean)=91

Amount of numbers=4

\frac{108+72+95+x}{4} =91\\275+x=91*4\\x=364-275\\x=89

Finally, the score that she will need is 89.

Fudgin [204]3 years ago
3 0
She needs a score of 89 for it to be an average of 91.00
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The value of correlation coefficient (r) for the dataset is 0.981

<h3>What is correlation coefficient (r)?</h3>

The correlation coefficient (r) is used to determine the closeness and association of a scatter plot points.

The dataset is given as:

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The correlation coefficient (r) is then calculated as:

r = \frac{\sum{((x - My)(Y - Mx)) }}{ \sqrt{((SSx)(SSy))}}

This gives

r = \frac{194.167 }{ \sqrt{((146.833)(266.833))}}\\

r = 0.9809

Approximate

r = 0.981

Hence, the value of correlation coefficient (r) for the dataset is 0.981

Read more about correlation coefficient at:

brainly.com/question/4219149

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