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kondaur [170]
3 years ago
14

When Sally went bowling, her scores were 108, 72, and 95. If she bowls a 4th game, what will her score need to be to give her an

average of 91?
Mathematics
2 answers:
tekilochka [14]3 years ago
8 0

Answer:

The answer is 89.

Step-by-step explanation:

In order to determine the score that she needs, we have to know about the mean. The <em>mean </em>is the average that we use frequently, where we add up all the numbers and then divide by the amount of numbers.

We have to make a equation where let be x the fourth score. Then:

First score=108

Second score=72

Third score=95

Fourth score=x

Average (mean)=91

Amount of numbers=4

\frac{108+72+95+x}{4} =91\\275+x=91*4\\x=364-275\\x=89

Finally, the score that she will need is 89.

Fudgin [204]3 years ago
3 0
She needs a score of 89 for it to be an average of 91.00
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Murljashka [212]
There is at least 90
4 0
3 years ago
Describe the transformations of how the graph y=x^2 can be transformed into y= -1/5 (x-4)^2 + 2
Orlov [11]

Answer:

Reflected over the x-axis, vertically shrunk by a factor of 1/5, moved right 4 units and up 2 units.

Step-by-step explanation:

Parent Graph: f(x) = a(bx - h)² + k

<em>a </em>is vertical stretch (a > 1) or shrink (a < 1) and reflection over x-axis

<em>b</em> is horizontal stretch or shrink and reflection over y-axis

<em>h</em> is horizontal movement left (if positive) or right (if negative)

<em>k</em> is vertical movement up (if positive) or down (if negative)

Now that we have our rules, we simply apply it to y = -1/5(x - 4)² + 2

<em>a</em> = -1/5, so reflection over x-axis and vertical shrink of 1/5 (1/5 < 1)

Nothing has changed <em>b</em>, so no horizontal stretch/shrink

<em>h</em> = -4, so horizontal movement right 4 units

<em>k</em> = 2, so vertical movement up 2 units

8 0
3 years ago
Please help i need to finish
elena-s [515]

Answer:

B. \overline A \overline C \cong \overline B \overline D

Step-by-step explanation:

The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that \overline D \overline C is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.

∴ \overline A \overline C \cong \overline B \overline D is the additional fact needed to prove \triangle ADC \cong \triangle BCD

Hope this helps :)

5 0
3 years ago
What is the surface area of this square pyramid?
Viefleur [7K]

base = 3*3 = 9 sq. in.

 side = 1/2 *3*6 = 9 sq. in.

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 Answer is A

3 0
3 years ago
Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. the length of the yard is 10 feet
Anna35 [415]
Let x be the yard length, then if <span>the length of the yard is 10 feet more than 2 times the width, the length of the yard is 2x+10. The perimeter is 2 lengths + 2 widths, so P=2x+2(2x+10) .
</span>
Since Sally <span>needs 56 feet of fencing to do the job, P=56 ft. and
</span>
<span>2x+2(2x+10)=56,
</span><span>
</span><span>2x+4x+20=56,
</span><span>
</span><span>6x=56-20,
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</span><span>6x=36,
</span><span>
</span><span>x=6 ft. and 2x+10=12+10=22 ft.
</span><span>
</span><span>Answer: The length of the yard is 22 feet</span>


4 0
3 years ago
Read 2 more answers
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