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kari74 [83]
3 years ago
13

Why is the amount of usable energy lower for anaerobic respiration than for aerobic respiration

Chemistry
1 answer:
photoshop1234 [79]3 years ago
3 0
Anaerobic is when there is not enough oxygen for aerobic respiration, so it uses glucose and lactic acid for example instead of glucose and oxygen for aerobic. Anaerobic takes longer to convert to energy. 
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padilas [110]
<span>The physical layers of the inner core and outer core form a single compositional layer.

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8 0
2 years ago
Alkanes are hydrocarbons containing only single bonds. Acyclic alkanes have carbon atoms arranged in chains, whereas cycloalkane
sashaice [31]

Answer:

156 Hydrogen atoms

Explanation:

<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:

CₙH₂ₙ₊₂

Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.

An acyclic alkane with 77 carbon atoms would thus have:

2*77 + 2 = 156 hydrogen atoms

4 0
3 years ago
Which of the following best defines the internal energy of a system?
Anarel [89]
 <span>In thermodynamics, the internal energy of a thermodynamic system, or a body with well-defined boundaries, denoted by U, or sometimes E, is the total of the kinetic energy due to the motion of molecules (translational, rotational, vibrational) and the potential energy associated with the vibrational and electric energy of atoms within molecules or crystals. It includes the energy in all the chemical bonds, and the energy of the free, conduction electrons in metals.</span>
7 0
3 years ago
Find the molar mass of this
kirill115 [55]

Explanation:

Given problem:

Find the molar mass of:

  SO₃ and C₁₀H₈

Solution:

The molar mass of a compound is the mass in grams of one mole of the substance.

To solve this, we are going to add the individual atomic masses of the elements in the compound;

  Atomic mass;

       S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol

For  SO₃;

     = 32 + 3(16)

     = 32 + 48

     = 80g/mol

For C₁₀H₈

      = 10(12) + 8(1)

      = 120 + 8

       = 128g/mol

7 0
2 years ago
an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?
Angelina_Jolie [31]
.02047 = x / 0.02105 = 0.0004309mol
6 0
3 years ago
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