Alloy: alloy, metallic substance composed of two or more elements, as either a compound or a solution. The components of alloys are ordinarily themselves metals, though carbon, a nonmetal, is an essential constituent of steel. ... See also amalgam; ferroalloy; intermetallic compound
Ceramic: A ceramic is any of the various hard, brittle, heat-resistant and corrosion-resistant materials made by shaping and then firing an inorganic, nonmetallic material, such as clay, at a high temperature. Common examples are earthenware, porcelain, and brick.
Synthetic polymer: Synthetic polymers are derived from petroleum oil, and made by scientists and engineers. Examples of synthetic polymers include nylon, polyethylene, polyester, Teflon, and epoxy. ... Vulcanized rubber is a synthetic (man-made) polymer, while pectin is an example of a natural polymer
That’s a *hint*
Explanation:
More is the electronegativity of atoms attached to the alpha carbon atom more will be the attraction of electron towards it. As a result, release of hydrogen ion will be easier.
Therefore, there will be increased in acidity of the compound.
Since, fluorine, chlorine and bromine are all group 17 elements and fluorine is more reactive than chlorine. On the other hand, chlorine is more reactive than bromine.
Hence, ability to attract the electrons towards itself will be maximum in fluorine and least in bromine.
Therefore, decreasing order of acidity of the given compounds is as follows.
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Answer:
150.5 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 35 °C
Final volume (V₂) = 5.5 L
Final temperature (T₂) =?
Next, we shall convert 35 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 35 °C
Initial temperature (T₁) = 35 °C + 273
Initial temperature (T₁) = 308 K
Next, we shall determine the final (i.e the new) temperature of air. This can be obtained as follow:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 308 K
Final volume (V₂) = 5.5 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
4 / 308 = 5.5 / T₂
Cross multiply
4 × T₂ = 308 × 5.5
4 × T₂ = 1694
Divide both side by 4
T₂ = 1694 / 4
T₂ = 423.5 K
Finally, we shall convert 423.5 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T₂ = 423.5 K
T₂ = 423.5 – 273
T₂ = 150.5 °C
Thus, the new temperature of the air is 150.5 °C