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3 years ago

Why is the amount of usable energy lower for anaerobic respiration than for aerobic respiration

1 answer:

3 0

Anaerobic is when there is not enough oxygen for aerobic respiration, so it uses glucose and lactic acid for example instead of glucose and oxygen for aerobic. Anaerobic takes longer to convert to energy.

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A scientist adds a liquid to a base. As it is added the substance turns reddish pink the liquid is most likely?

Natalka [10]

Answer:

what we need to answer here?

6 0

3 years ago

Which type of fat is a solid at room temperature and does not have double bonds between carbon

melamori03 [73]

Answer:

Saturated Fats

Explanation:

Saturated fats are all of the above.

Also, Saturated fat is very unhealthy. Only consume it in small amounts.

7 0

2 years ago

Read 2 more answers

Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz

stiv31 [10]

Answer: Freezing point of a solution will be $-1.16^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

3 0

2 years ago

Which answer below correctly identifies the type of change and the explanation when magnesium comes into contact with hydrochlor

Oliga [24]

Answer:

A chemical change because a temperature change occurred, the solid disappeared and a gas was produces

Explanation:

Magnesium reacts with hydrochloric acid releasing energy, and leading to the formation of magnesium chloride and hydrogen gas. This is represented by the equation below:

Mg₍s₎ + 2HCl₍aq)⇒ MgCl₂₍aq₎ + H₂₍g₎

5 0

3 years ago

Read 2 more answers

A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.

joja [24]

For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1) × 100% = 0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

5 0

3 years ago