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Arlecino [84]
2 years ago
10

How many different products can be formed from a poorly planned crossed aldol addition?

Chemistry
2 answers:
Lerok [7]2 years ago
6 0

There are four different products can be formed from a poorly planned crossed aldol addition.

So the correct option is D

Two distinct ketone and aldehyde reactants are used in a crossed condensation reaction. Due to presence of distinct ketone and aldehyde reactants there are possibility of formation of several enolate ion nucleophiles as well as multiple carbonyl electrophile .

Example : Ethanal and propanone undergoes cross-aldol condensation reaction and give results in two products.

First case: ethanal acts as enolate ion

Second case: propanone acts as enolate ion

Third case: when self condensation is also a product.

to learn more about aldol addition

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zheka24 [161]2 years ago
3 0

There are 4 different products will be formed from a poorly planned crossed aldol addition.

In a crossed aldol condensation, two distinct ketone and aldehyde reactants are used. Due to the possibility of several enolate nucleophiles as well as multiple carbonyl electrophiles, similar reactions typically result in a variety of distinct condensation products.

Ethanol and propanol undergo cross-aldol condensation, which results in two products:

  • one where ethanol serves as an enolate ion and the other where propanol serves as an enolate ion.
  • 2-Methylbut-2-enal and Pent-2-enal are just the two cross-aldol derivatives.

Therefore, the correct answer will be option (d)

To know more about products

brainly.com/question/28027128

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Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
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<u>Given:</u>

Calculated density values-

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<u>To determine:</u>

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<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

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For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

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