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mezya [45]
3 years ago
8

Arrange the following compounds in decreasing order of acidity from left to right, and explain the reason in less than 90 words.

CH3COOH CC13COOH CF3COOH CBr3COOH
Chemistry
1 answer:
saveliy_v [14]3 years ago
8 0

Explanation:

More is the electronegativity of atoms attached to the alpha carbon atom more will be the attraction of electron towards it. As a result, release of hydrogen ion will be easier.

Therefore, there will be increased in acidity of the compound.

Since, fluorine, chlorine and bromine are all group 17 elements and fluorine is more reactive than chlorine. On the other hand, chlorine is more reactive than bromine.

Hence, ability to attract the electrons towards itself will be maximum in fluorine and least in bromine.

Therefore, decreasing order of acidity of the given compounds is as follows.

        CF_{3}COOH >  CCl_{3}COOH > CBr_{3}COOH > CH_{3}COOH

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Density of the vinegar is higher than the density of the oil.

Explanation:

Density of the vinegar is higher than the density of the oil. The consequence of this is that the oil will be the top layer in the pitcher while the vinegar is at the bottom layer in the pitcher.

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3 years ago
2 planets are over 4 million light years away. Explain how you would use a ray of light to determine which planet is farther awa
grigory [225]
Https://earthsky.org/space/what-is-a-light-year
4 0
3 years ago
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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
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n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
If you take a part time job while you are still in school what might your opportunity scost be
yarga [219]

The opportunity costs of working part-time while attending high school could be studying time, grades, and your own free time. It depends on the person, how they do in school, but if it were for me, I would say the benefits outweigh the costs. I have enough time to study and still get good grades in school.

7 0
2 years ago
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A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
3 years ago
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