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2 years ago

A scientist collects a core sample from 60 km deep in Earth,

Chemistry

1 answer:

geniusboy [140]2 years ago

5 0

C because this is not very deep and towards the surface you are more likely to find solid rocks

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You are experimenting to find out if fertilizer makes a plant grow taller. What would be an appropriate control group for this e

leonid [27]

Answer:

If plants are given nitrogen fertilizer, then they will grow taller. ... Factors in an experiment that a scientist PURPOSELY Changes (manipulated) Control Group ... to test various amounts of fertilizer to find out what amount makes plants grow

Explanation:

3 0

2 years ago

Solid solution of a metal or nonmetal dissolved in a metal

guajiro [1.7K]

An alloy is the solid solution of a metal or non-metal dissolved in a metal.

3 0

3 years ago

How many moles of nitric acid are present in 35.0 ml of a 2.20 M solution?

vodomira [7]

Answer:

There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

Explanation:

Molarity of the solution = 2.20 M

$Molarity=\frac{number\:of\:moles}{Volume\:of\:Solution\:in\:L}\\\\Number\:of\:moles=Molarity\times(Volume\:of\:Solution\:in\:L)\\\\Volume\:of\:Solution=35\:mL=35\times10^{-3}L\\\\Number\:of\:moles=2.20\times35\times10^{-3}=77\times10^{-3}\:moles\:of\:HNO_{3}$

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

8 0

3 years ago

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

Gelneren [198K]

Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

3 0

3 years ago

A 6 kg rock is sitting at the edge of a 100 m tall cliff. What is the potential energy of the rock with respect to the ground?

Hatshy [7]

Potential energy can be calculated by the formula Pe=mgh. Plug in your values:

Pe=mgh
Pe=(6 kg)(9.8m/s^2)(100 m)
Pe=5880 kg x m^2/s^2, or 5880 Joules

5 0

2 years ago