2H₂ + O₂ → 2H₂O
mole ratio of O₂ : H₂O is 1 : 2
∴ if moles of O₂ = 16 mol
then moles of H₂O = (16 mol × 2)
= 32 mol
Explanation:
The given reaction will be as follows.

So, equilibrium constant for this equation will be as follows.
![K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D%5BH_%7B2%7D%5D%5E%7B2%7D%7D)
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
![K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D%5BH_%7B2%7D%5D%5E%7B2%7D%7D)
= 
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
A2+. Group 2 elements form cations with 2+ charge.
Answer:
the answer to that question is d