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Aleks [24]
3 years ago
8

What is the significance of the spin quantum number.

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
6 0
Is a quantum number the parameterizes the
intrinsic angular momentum of any given
particle.
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Use your understanding of the ideal gas law to identify the correct relationships among the variables. Pressure is . Temperature
MAXImum [283]

Answer:

Pressure is inversely proportional to the volume of a gas at constant temperature and number of moles

Temperature is directly proportional to volume at constant pressure and number of moles

Volume is directly proportional to the number of moles of a gas at constant temperature and pressure

Explanation:

The ideal gas law is derived from a combination of the Boyle's, Charles' and Avogadro's law of gases.

Boyle's law states that at constant temperature, the volume of a given mass of gas (number of moles of gas is constant) is inversely proportional to the pressure exerted by the gas.

V ∝ 1/P (at constant n, T)

Charles'law states that at constant pressure, the volume of a given mass of gas (constant amount, n) is directly proportional to the temperature of the gas; V ∝ T (at constant n, P)

Avogadro’s law states that at constant temperature and pressure, the volume of a given mass of gas is directly proportional to the number of moles of gas present; V ∝ n(at constant T, P)

Combining the three equations gives the following relationship: V ∝ nT/P

By inserting a proportionality constant called the molar gas constant, R, in the relationship above, the ideal gas equation is derived as follows:

V = nRT/P or PV = nRT

5 0
3 years ago
Read 2 more answers
what is the volume of a book that has a width of 10cm,a length that is 2 times the width,and a height that is half the width​
Masteriza [31]

width=10cm

length=2xwidth=2x10=20cm

height=width/2=10/2=5

V=w*l*h=10*20*5=1000cm^3

5 0
3 years ago
Read 2 more answers
What is the balanced equation for the combustion of sulfur
Alex17521 [72]

Answer:

There are three possible chemical equations for the combustion of sulfur:

  • 2S (s)  + O₂ (g)  → 2SO (g)

  • S (s) + O₂ (g) → SO₂ (g)

  • 2S (s) + 3O₂ (g) → 2SO₃ (g)

Explanation:

<em>Combustion</em> is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.

<em>Sulfur</em> iis a nonmetal, so the oxide formed is a nonmetal oxide.

The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.

The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).

Then you have three different equations for sulfur combustion:

<u>1) Oxidation number +2:</u>

  • S(s) + O₂(g) → SO(g)

Which when balanced is: 2S(g) + O₂(g) → 2SO(g)

<u>2) Oxitation number +4:</u>

  • S(s) + O₂(g) → SO₂(g)

That equation is already balanced.

<u>3) Oxidation number +6:</u>

  • S(s) + O₂(g) → SO₃(g)

Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)

3 0
4 years ago
Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). (3 points)
AleksandrR [38]

Answer:

1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left

Explanation:

Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.


Adding a catalyst has no effect on equilibrium reactions.

When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.

5 0
2 years ago
Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR
ycow [4]

Answer:

[CaCl₂] = 1.32 M

Explanation:

We know the volume of solution → 0.30 L

We know the mass of solute → 44 g of CaCl₂

Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L  = 1.32 M

6 0
3 years ago
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