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3 years ago

What is the value of the expression 5³√-27+4√25

Mathematics

1 answer:

MakcuM [25]3 years ago

8 0

Answer:

669.51905283 or 375 √3 + 20

Step-by-step explanation:

Raise 5 to the power of 3

125√27 + 4√25

Rewrite 27 as 3²·3

Factor 9 out of 27

125√9(3) + 4√25

Rewrite 9 as 3²

125√3²·3 + 4√25

Pull terms out from under the radical

125(3√3) + 4√25

Multiply 3 by 125

375√3 + 4√25

Rewrite 25 as 5²

375√3 +4√5²

Pull terms out from under the radical, assuming positive real numbers

375√3 + 4 · 5

Multiply 4 by 5

375 √3 + 20

Exact form: 375 √3 + 20

Decimal form: 669.51905283

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Help, please

Elanso [62]

Answer: 10.5 is my guess

Step-by-step explanation:

1. 30% = 8.4

100 x

cross multiply

30(x) = 840

divide both sides by 30 = 28

2. 37.5% = y

100 28

cross multiply

1050 = 100y

divide both sides by 100 = 10.5

5 0

3 years ago

Question 15

Lemur [1.5K]

I make you like it when you do 67

4 0

3 years ago

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

Here for constructing 95% confidence interval we have used chi-square test statistics.

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

95% confidence interval for $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0

4 years ago

I need help on this.

diamong [38]

Answer:

hello

Thanh have 3,5 meters of fabric. i can say

3,5/1 for it.

and i can say 35/10

now he used three-fourths of a meter of fabric.

its equal to 3/4

now i have to remove 3/4 from 35/10.

35/10 - 3/4

denominators have to be same thats why im expanding them to 20.

35×2/10×2 = 70/20

3×5/4×5 = 15/20

now i can remove 15/20 from 70/20!

70/20 - 15/20 = 55/20

we cannot see 55/20 in the options.

thats why im dividing them with 5.

55÷5= 11 20÷5=4

the answer is 11/4

11/4 = 2and 3/4

so its option 2

good luck(:

7 0

3 years ago

What’s the height of a right triangle with an angle that measures 45 degrees and a base of 16?

nikklg [1K]

I got h = 11.31371.

Hope this helps!

7 0

3 years ago