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vivado [14]
3 years ago
13

Oreos 2.98 for 15.5.Oz or chips ahoy for 2.50 for 14.Oz I pick chips ahoy BUT ITS ASKING UNIT RATE CENTS PER OZ

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

Unit rate of oreos = 19.23 cents/oz

Unit rate of Chips Ahoy = 17.86 cents/oz

The cheapest and most affordable is the chips ahoy because it has a lower unit rate.

Step-by-step explanation:

Oreos 2.98 for 15.5.Oz or chips ahoy for 2.50 for 14.Oz I pick chips ahoy BUT ITS ASKING UNIT RATE CENTS PER OZ

We would be finding the Unit Rate of each product.

For Oreos

Oreos $2.98 for 15.5.Oz

We convert dollars to cents

1 dollars = 100 cents

2.98 dollars = x

x = 2.98 × 100 cents

= 298 cents

Hence, the unit rate in cents/oz

= 298 cents/15.5 oz

= 19.225806452 cents/oz

= 19.23 cents/oz

For Chips ahoy

$2.50 for 14.Oz

We convert dollars to cents

1 dollars = 100 cents

2.50 dollars = x

x = 2.50 × 100 cents

= 250 cents

Hence, the unit rate in cents/oz

= 250 cents/14 oz

= 17.857142857 cents/oz

= 17.86 cents/oz

Therefore, the cheapest and most affordable is the chips ahoy because it has a lower units rate.

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Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

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Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

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Step-by-step explanation:

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