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natima [27]
3 years ago
12

Use inverse operations to complete the second equation each time

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

a) 55-42=13

b) 29-10=19

c) 65÷5=13

d) 72÷8=9

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Solve<br><br> 1/5 (x+3)=−(2x+3)
Rasek [7]

Answer:

Step-by-step explanation:

just simplify the LHS first.

You can either multiply 1/5 by (x+3) and then solve

or

multiply both sides by 5 to get rid of 1/5 on LHS

I will multiply by 5

(x+3)= -10x-15     ( 5*1/5(x+3)= -5(2x+3)

now rearrange the equation

x+3=-10x-15

-10x-15-x-3=0

-11x-17=0

-11x=17

x= -17/11

4 0
2 years ago
Which angles are adjacent angles?
Pepsi [2]
C, B, G  common vortex ( B) and common side (C, G) 


8 0
3 years ago
200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

6 0
1 year ago
What is the solution of log3x − 5 16 = 2?
Stolb23 [73]

Answer:

log (16)=2 in base 3x-5

==>16=2^(3x-5)

==>2^4=2^(3x-5)

==>4=3x-5

==>3x=9

==>x=3

Step-by-step explanation:

4 0
2 years ago
Whats the surface area of a cylinder with height of 12in.and the radius is 4in​
emmainna [20.7K]

Answer:

401.92 in²

Step-by-step explanation:

S.A. = 2πr²+2πrh

S.A. = 2π4²+2π4·12

S.A. = 100.48 + 301.44

S.A. = 401.92 in²

7 0
3 years ago
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