Quiet and wet because it is in the sea
Answer:
B
Explanation:
B is your answer because the clone would have identical genetic traits but differ in the traits the original acquired during its life.
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Answer:
The results can be explained if the mutation for bag wings is sex-linked, dominant, and lethal in males.
Explanation:
When a trait is differently expressed in males and females, we must suspect that it's sex-linked.
If we consider the mutation for bag wings as sex-linked and dominant (B), and the wild-type allele (B+) is recessive, then the<u> expected offspring</u> resulting from the cross between a bag-winged female XᴮXᴮ⁺ (heterozygous) and a WT male Xᴮ⁺Y would be:
- 1/4 XᴮXᴮ⁺ bag-winged female
- 1/4 Xᴮ⁺Xᴮ⁺ wild-type female
- 1/4 Xᴮ⁺Y wild-type male
- <u><em>1/4 XᴮY bag winged male</em></u>
But the bag-winged male doesn't appear in the progeny, and the observed proportions of the other phenotypes are 1/3 each. This suggests that the mutation is lethal in males, and maybe in homozygosis in females as well.
Answer:
9.3/3=x/2,
Explanation:
9.3/3=x/2, where 9.3 is the new number of moles of O2, and 3 and 2 are the stoichiometric coefficients of O2 and H2S in the reaction. Solving for x yields that we need 6.2 moles of H2S to use all of the O2.