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Dmitrij [34]
3 years ago
11

If you can see the blinking insertion point in a field, you are in ________.

Physics
1 answer:
Sonja [21]3 years ago
7 0
You would be in an editing mode when you can see a blinking insertion point on a field. In addition, in any word processing software, it would basically signify that you can already type on the document. Another name for the insertion point would be the I-beam as displayed on the screen.
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Displacement is which of the following types of quantities?A. vectorB. scalarC. magnitudeD. dimensional
agasfer [191]

Answer: A. vector

Explanation:

Movement is the change of position of a body at a certain time. The body that experiences this change of position is called mobile.

In this sense, the <u>displacement</u> is the distance in a straight line between the initial and final position of this mobile, which differentiates it from <u>the trajectory, </u> which is the <u>path followed by the body in its movement and a scalar magnitude.</u>

Hence, the displacement is a vector.

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Does earths surface heat up the same everywhere
melomori [17]

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4 0
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3 years ago
A metal object is suspended from a spring scale. The scale reads 920 N when the object is suspended in air, and 750N when the ob
Ostrovityanka [42]

17.3 L.

<h3>Explanation</h3>

The object appears 920 - 750 = 170\;\text{N} lighter in water than in the air. Water has supplied that 170 N of buoyant force.

The size of the buoyant force on an object in water is the same as the weight of water that the object has displaced. The buoyant force on the metal object here is 170 N. The object must have displaced water of the same weight.

g = 9.81 \;\text{N}\cdot\text{kg}^{-1}.

Mass of water displaced:

\text{Mass} = \dfrac{\text{Weight}}{g} = \dfrac{170}{9.81} = 17.3 \;\text{kg}.

Volume of water displaced:

The density of water at room temperature is 1.000\;\text{kg}\cdot\text{dm}^{-3}. Each kilogram of water will occupy a volume of 1 dm³ (one cubic decimeter), which is the same as 1 L (one liter).

V = \dfrac{\text{Mass}}{\text{Density}} =\dfrac{m}{\rho} = \dfrac{17.3\;\text{N}}{1.000\;\text{kg}\cdot\text{dm}^{-3}} = 17.3\;\text{dm}^{-3}=17.3\;\text{L}.

Volume of the object:

The object is completely under water. As a result, the volume of the object will be the same as the volume of water displaced. The volume of the object is also 17.3 L.

3 0
3 years ago
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