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aev [14]
4 years ago
8

A woodworker has made four

Physics
2 answers:
3241004551 [841]4 years ago
7 0

Answer:

I think the answer is b

Explanation:

yes its b I just did this prob on my notebook

Lilit [14]4 years ago
6 0
I think the answer is b
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A 1.5kg cannon is loaded with a 0.52 kg ball . The cannon is ignited and launches the ball forward with speed of 75m/s. Determin
Mila [183]

Answer:

-26 m/s (backward)

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum momentum of the cannon + ball system must be conserved before and after the explosion.

Before the explosion, they are both at rest, so the total momentum is zero:

p = 0

After the explosion, the total momentum is:

p=MV+mv

where

M = 1.5 kg is the mass of the cannon

m = 0.52 kg is the mass of the ball

v = +75 m/s is the velocity of the ball

V is the velocity of the cannon

Since the momentum is conserved, we can equate the two expressions:

0=MV+mv

And solving, we find V:

V=-\frac{mv}{M}=-\frac{(0.52)(+75)}{1.5}=-26 m/s

where the negative sign means the direction is opposite to that of the ball.

4 0
4 years ago
Calculate the specific gravity of a pure gold nugget (ρ = 19.3 g/cm3)
Natasha2012 [34]
We know, For a substance they both are equal in magnitude, i.e., 

Specific Gravity = Density 
Specific Gravity = 19.3      [ As Density = 19.3 ]

In short, option C would be your correct Answer!

Hope this helps!
7 0
3 years ago
LOOKING FOR ALL YOU SCIENTISTS!!
tensa zangetsu [6.8K]

Answer:

Make sure you're getting paid. Unpaid interships are a complete and total waste.

Explanation:

7 0
3 years ago
Read 2 more answers
The net external force on a golf cart is 395.2 n north. if the cart has a total mass of 259.1 kg, what is the cart's acceleratio
yKpoI14uk [10]
Applying the Newton Second Law of motion that is F=ma
We have F=395.2N (North) and m=259.1Kg

Putting these values in the equation

395.2 = 259.1 x a than
for a = 395.2/259.1
a = 1.525 m/sec 2
8 0
3 years ago
What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)
puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

3 0
3 years ago
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