<h2>
Answer:</h2>
38.14Ω
<h2>
Explanation:</h2>
Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;
V = I R -------------------(i)
<em>Where</em>;
R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)
<em>From the question;</em>
V = 18.5V
I = 0.485A
<em>Substitute these values into equation (i) as follows;</em>
18.5 = 0.485 x R
<em>Solve for R;</em>
R = 18.5 / 0.485
R = 38.14Ω
Therefore the resistance of the bulb is 38.14Ω
Answer:
force=337.5N
accelertion=5.63ms^-2
Explanation:
please find the answers in the pictures above maam or sir.
Answer:
0.5 m/s2
Explanation:
Step 1:
Data obtained from the question.
Total Mass = 60Kg
Net force = 30N
Acceleration =?
Step 2
Determination of the acceleration.
Force = Mass x Acceleration.
With the above equation, we can easily obtain the acceleration as follow:
30 = 60 x Acceleration
Divide both side by 60
Acceleration = 30/60
Acceleration = 0.5 m/s2
Now, we can thus say that the acceleration at that moment is 0.5 m/s2
Answer:
2ms-¹ means that the body under consideration moves 2m in a second, and may be it will continue to move 2m in every 1 second, if there's no external unbalanced force acting on that body (those forces do include frictional forces). mark its brainlist plz. Kaneppeleqw and 6 more users found this answer helpful. Thanks 3.
In order for particles to perform a simple harmonic motion, we must follow the law of force of the form F = -kx, where x is the displacement of the object from the equilibrium position and k is the spring constant. The
force shown in <span>F = -kx is always the restoring force in the sense
that the particles are pulled towards the equilibrium position.
The
repulsive force felt when the charge q1 is pushed into another charge
q2 of the same polarity is given by Coulomb's law
F = </span><span>k *q1* q2 / r^2.
</span>It is clear that Coulomb's law is an inverse-square relationship. It does not have the same mathematical form as the equation <span><span>F = -kx.</span> Thus,
charged particles pushed towards another fixed charged particle of
the same fixed polarity do not show a simple harmonic motion when
released. Coulomb's law does not describe restoring force. When q1 is released, it just fly away from q2 and never returns.</span>
