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2 years ago

A reliable source of information on groundwater is always

Chemistry

2 answers:

never [62]2 years ago

7 0

Up to date.

Hope this helps

balandron [24]2 years ago

3 0

Http://water.ky.gov/groundwater/Pages/GroundwaterAwareness.aspx

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A sample of silver (Ag) contains 3.011x1023 atoms. How much does this

Ugo [173]

Answer:

53.93 g Ag

Explanation:

3.011x1023 atoms Ag x 1 mole Ag x 107,8683 grams =

6.022x $10^{23}$ atoms 1 mole Ag

use the periodic table fo find Ag atomic mass and use Avogadro´s number

3 0

2 years ago

The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921

mixas84 [53]

The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

The percentage error of a measurement can be calculated by following the following process:

Find the difference between the true value and the measured value of a quantity.
Then, divide by the true value and then multiplied by 100

The true value of the density of iron is 7.874 g/mL
Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

Learn more: brainly.com/question/18074661?referrer=searchResults

5 0

1 year ago

A solution is prepared by dissolving ammonium sulfate in enough water to make of stock solution. A sample of this stock solution

Pani-rosa [81]

Answer: molarity of ammonium ions = 0.274mol/L

molarity of sulfate ions = 0.137mol/L

Note: The complete question is given below

A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of stock solution. A 10.00-mL sample of this stock solution is added to 50.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution.

Explanation:

Molar concentration = no of moles/volume in liters

no of moles = mass/molar mass

mass of ammonium sulfate = 10.8g, molar mass of ammonium sulfate, (NH₄)₂SO₄ = (14+4)*2 + 32+ (16)*4 = 132g/mol

no of moles = 10.8g/132g/mol = 0.0820moles

Molarity of stock solution = 0.0820mol/(100ml/1000ml* 1L) = 0.0820mol/0.1L Molarity of stock solution = 0.820mol/L

Concentration of final solution is obtained from the dilution formula,

C1V1 = C2V2

C1 = 0.820M, V1 = 10mL, C2 = ?, V2 = 60mL

C2 = C1V1/V2

C2 = 0.820*10/60 = 0.137mol/L

molar concentration of ions = molarity of solution * no of ions

molarity of ammonium ions = 0.137mol/L * 2 = 0.274mol/L

molarity of sulfate ions = 0.137 mol/L * 1 = 0.137mol/L

4 0

3 years ago

For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,

BartSMP [9]

A) 4400 kj of heat released into surroundings

<h3>Further explanation</h3>

Reaction

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ

Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8

So for two moles of C3H8, the enthalpy :

$\tt -2200\times 2=-4400~kJ$

7 0

2 years ago

In the formula 5CaSO4 the total number of sulfur atoms present is a. 1. b. 5. c. 9. d. 20?

podryga [215]

The answer is b . (1*5=5)

4 0

3 years ago

Read 2 more answers