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lianna [129]
3 years ago
8

Find the value of a in the equation 6a-7=3a+14

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

a=7

Step-by-step explanation:

Given,

6a-7=3a+14

or,6a-3a=14+7

or,3a=21

or,a=7 [ANSWER]

NNADVOKAT [17]3 years ago
3 0

Answer:

a = 7

Step-by-step explanation:

6a - 7 = 3a + 14

( Minus 3a from both sides to isolate + 14 )

3 a - 7 = 14

( Minus 7 from both sides to isolate 3a )

3a = 21

( Divide both sides by 3 to isolate a )

a = 7

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PLEASE HELP ME!!! Thank you SO MUCH! Explain your answer
soldi70 [24.7K]

Answer:

y = -.5x -.5

Step-by-step explanation:

All you do is plug in the x and y in the point to the equation, y = mx + b. Since the coordinate is (5, -3), this in the equation would look like -3 = -.5(5) +b. (all you need to find is the y-intercept, or b.) Solve it out to get -3 = -2.5 + b. Add 2.5 to each side of the equation, you're left with b = -.5. Now, put that back into the original equation, and get y = -.5x -.5. I think this is right, you can go back through and check once more if you'd like.

8 0
3 years ago
Greg has four different colored cards in a box. Yellow, red, blue, and green. He randomly selects one card, records the color, a
Veronika [31]

Answer:

He should expect to select 75 yellow cards.

Step-by-step explanation:

Since there is replacement, for each trial, we have:

1 yellow card

1 red card

1 blue card

1 green card.

If Greg does this 300 times, how many yellow cards should he expect to select?

Each trial, there are 4 cards, one of which is yellow. So 1/4 = 0.25 probability of selecting a yellow card.

Over 300 trials

0.25*300 = 75

He should expect to select 75 yellow cards.

6 0
3 years ago
Find the solution to the system of equations.
goldenfox [79]

Substitute

4x+2=x-4

Then solve

3x=-6

x=-2

Substitute answer into an equation to find y

y=-2-4

y=-6

So you solution is:

(-2,-6)

8 0
3 years ago
Describe the translation of the function from the parent function f(x) = x².
kkurt [141]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\

\end{array}\\

\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


now, notice the template above... now let's see your function \bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}

so.. what do you think was the shift then?
8 0
3 years ago
Which expression is equivalent to 15 – 5x?
ahrayia [7]

Answer:

15 - 5x = 5 · 3 - 5 · x = 5(3 - x)

3 0
3 years ago
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