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Vlad [161]
3 years ago
13

A wheel of radius 14 inches is rotating 0.5 rad/s. what is the linear speed v, the angular speed in rpm, and the angular speed i

n deg/s?
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

First, let us find for the linear speed v. The formula for this is:

v = r w

where r is radius and w is radial velocity, therefore the linear speed is:

v = 14 inches (0.5 rad / s)

v = 7 inches / s

 

Now calculating for angular speed in rpm or revolutions per minute:

angular speed in rpm = (0.5 rad / s) (1 rev / 2π rad) (60 s / min)

<span> angular speed in rpm = (15/π) rpm = 4.77 rpm</span>

 

Finally calculating for angular speed in deg per second:

angular speed in rpm = (0.5 rad / s) (360° / 2π rad)

<span> angular speed in rpm = (90/π) deg/s = 28.65 deg/s</span>

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Answer:

1.) Longitudinal waves

2.) Transverse waves

3.) Longitudinal waves

Explanation:

The sound of one whale calling another whale underwater.  is a longitudinal wave since the medium, in this case the body of water, is vibrating parallel to the direction of propagation of the wave.

A pulse sent down a stretched rope by snapping one end of it. ( transverse wave) because its oscillations are perpendicular to the direction of the wave or path of propagation

The vibrations in a guitar string

Longitudinal wave. Because its oscillations are parallel to the direction of the wave or path of propagation

5 0
3 years ago
A 50.0 kg object rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and
MariettaO [177]

Answer:

f=140\ N

Explanation:

Given:

  • mass of the object on a horizontal surface, m=50\ kg
  • coefficient of static friction, \mu_s=0.3
  • coefficient of kinetic friction, \mu_k=0.2
  • horizontal force on the object, F=140\ N

<u>Now the value of limiting frictional force offered by the contact surface tending to have a relative motion under the effect of force:</u>

F_s=\mu_s.N

where:

N= normal force of reaction acting on the body= weight of the body

F_s=0.3\times (50\times 9.8)

F_s=147\ N

As we know that the frictional force acting on the body is always in the opposite direction:

So, the frictional force will not be at its maximum and will be equal in magnitude to the applied external force and hence the body will not move.

so, the frictional force will be:

f=140\ N

8 0
3 years ago
If y^2= 3.249 x 10^-11, y = ?
Leni [432]

Answer:

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

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7.17m/s glad I could help
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Vx = + 4.33 m/s. Hope this helps
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