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agasfer [191]
3 years ago
5

How many hats did the knitter who sold 5 scarves sell?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0
Zero, if she sold 5 scarves & it doesn’t say anything about hats
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Show me how to solve 10>x/2 +4
postnew [5]

Treat this as if the inequality sign was the same thing as an equal sign. Most of the equality rules apply to inequalities (with a few exceptions)

10>\dfrac{x}{2}+4

Subtract both sides by 4

10-4>\dfrac{x}{2}+4-4

6>\dfrac{x}{2}

Multiply both sides by 2

2\times6>\dfrac{x}{2}\times2

12>x

We want the unknown variable on the left side (because it looks nicer)

x

5 0
4 years ago
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Yolanda’s club require that 60% of the members be present for any vote. If at least 30 members must be present to have a vote ho
balandron [24]
We can rewrite this problem as:
What is 60% of 35?
"Percent" or "%" means "out of 100" or "per 100", Therefore 60% can be written as
60
100
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When dealing with percents the word "of" means "times" or "to multiply".
Finally, lets call the number of members we are looking for "m".
Putting this altogether we can write this equation and solve for
m
while keeping the equation balanced:
m
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60
100
×
35
m
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2100
100
m
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members must be present to have a vote.
8 0
3 years ago
Read 2 more answers
Solving for x... please help me....​
geniusboy [140]

Answer:

A) 11

Step-by-step explaination:

CE = 2x - 2

CE = CD + DE

= x + 9

Hence it can be said that,

2x - 2 = x + 9

2x - x = 9 + 2

x = 11

6 0
3 years ago
F(X)=X^3 + 4 X^2-10=0 (between X=1 , X=2) بطريقه ال Bisection method<br><br>please fast​
svetlana [45]

I hope it's helpful for u but I am not sure my answer is right !

6 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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