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Sladkaya [172]
3 years ago
6

What is the solution to the following system of equations?

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer: (5,0)

Step-by-step explanation:

x - 3y =5 -----------(1)

2x + y = 10 ----------(2)

By elimination method, multiply eqn(1) by 2

2x - 6y = 10 ------------(3)

eqn(3) - eqn(2)

-7y = 0

Divide bothside by -7

y= 0

Now, we substitute the value of y in eqn(1)

x - 3(0) = 5

x - 0 = 5

x=5

Therefore,x=5 and y=0

AlekseyPX3 years ago
6 0
X=5+3y
10+6y+y=10
7y=0
y=0
x=5
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