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Arada [10]
3 years ago
13

Which ordered pair can be included in the table of values shown below for the equation p = 25 x minus 2? x 3 9 5 10 p 73 223 123

248 (negative 2, negative 2) (negative 2, 0) (0, negative 2) (0, 0)
Mathematics
2 answers:
djyliett [7]3 years ago
6 0

Answer:

C (0,-2)

Step-by-step explanation:

zhenek [66]3 years ago
5 0

Answer:

(0, negative 2)

Step-by-step explanation:

p = 25x - 2

When x = -2, p = 25(-2) - 2 = -52.

When x = 0, p = 25(0) - 2 = -2.

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What is an equation of the line that passes through the points (-4, 2) and<br> (-8,3)?
inn [45]

Answer:

y = --0.25x + 1

Step-by-step explanation:

In order to find the equation of a line, you must first find the slope of the line.

The equation to find slope is  \frac{y_2 - y_1}{x_2 - x_1}.

Plug in the given points:

(x2, y2) = (-8,3)

(x1, y1) = (-4,2)

(y2 - y1) / (x2 - x1) = (3-1)/ (-8 - -4) = (3-2) / (-8 + 4) = 1/-4 = -0.25

Next, you solve for the y-intercept using one of the two coordinates:

y = -0.25x + b

2 = -0.25(-4) + b

2 = 1 + b

b = 2 - 1 = 1

y = -0.25x + 1

4 0
3 years ago
Find the number of ways to distribute six different toys to three different children such that each child gets at least one toy.
Lisa [10]

Answer:

Step-by-step explanation:

Given that there are six different toys and they are to be distributed to three different children.

The restraint here is each child gets atleast one toy.

Let us consider the situation as this.

Since each child has to get atleast one toy no of ways to distribute

any 3 toys to the three children each.  This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways

So 3 toys to each one in 6x5x4 =120 ways

Now remaining 3 toys can be given to any child.

Hence remaining 3 toys can be distributed in 3x3x3 =27 ways

Total no of ways

= 120(27)

= 3240

8 0
3 years ago
Suppose that F(x) = x^2 and G(x) = 2x^2-5. Which statement best compares the graph G(x) with the graph of F(x)?
notsponge [240]
I believe the correct answer from the choices listed above is option  D. The graph <span>G(x) as compared to the graph of F(x) would be that the </span><span>graph of G(x) is the graph of F(x) stretched vertically and shifted 5 units down. 2 is a stretch factor and -5 is the shift downwards of the graph. Hope this answers the question.</span>
8 0
3 years ago
Read 2 more answers
How do you solve this problem? With work!!
Evgesh-ka [11]
You would put 9 times v because you are multiplying it to the 9 and you do not know what v is then you would divide it by 3 and get your answer so for example if you should have gotten 9 times v = 72 then 72 divided by 3 = 24 and 24 divided by 3 = 8

7 0
4 years ago
Read 2 more answers
You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
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