Answer:
the average number of car(s) in the system is 1
Step-by-step explanation:
Given the data in the question;
Arrival rate; λ = 2.5 cars per hour
Service time; μ = 5 cars per hour
Since Arrivals follows Poisson probability distribution and service times follows exponential probability distribution.
Lq = λ² / [ μ( μ - λ ) ]
we substitute
Lq = (2.5)² / [ 5( 5 - 2.5 ) ]
Lq = 6.25 / [ 5 × 2.5 ]
Lq = 6.25 / 12.5
Lq = 0.5
Now, to get the average number of cars in the system, we say;
L = Lq + ( λ / μ )
we substitute
L = 0.5 + ( 2.5 / 5 )
L = 0.5 + 0.5
L = 1
Therefore, the average number of car(s) in the system is 1
Step-by-step explanation:
Maybe you forgot to put a picture, because 10z-3 is the most simple form. You can't simplify.
Answer:
Step-by-step explanation:
All of that anything you want actually
The answer will be
155 times 5 = 775
