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3 years ago

How many gallons of water were in the bucket after 1 second? (Hint: Type your answer as a fraction.)

Mathematics

2 answers:

olasank [31]3 years ago

6 0

Answer:

1/2 gal

Step-by-step explanation:

Sunny_sXe [5.5K]3 years ago

5 0

Answer:

i dont know maybe a half gallon not sure have a good day tho stay safe

Step-by-step explanation:

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How would I solve this?? 5p-8(p+1)>16

alexandr402 [8]

*To solve inequalities is similar to solving equations: isolate the desired variable to one side.

So firstly, distribute -8 to (p + 1):

$5p-8p-8>16$

Next, combine like terms:

$-3p-8>16$

Next, add 8 to both sides:

$-3p>24$

Lastly, divide both sides by -3. Now since you are dividing by a negative, you will be flipping the inequality symbol as well. Your final answer will be $p$

6 0

3 years ago

What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"

salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is $27 + 64x^{3}$

Now, the equation is $27 + 64x^{3} = 0$

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be $- \frac{3}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.

Again, we have to solve the difference of two cubes which is $64m^{3} - 1$

Now, the equation is $64m^{3} - 1 = 0$

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be $\frac{1}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)

8 0

3 years ago

Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j

Tatiana [17]

Answer:

$\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

Step-by-step explanation:

$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$