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3 years ago

2. Osmium is a very dense metal. What is its density in g/cm3 if 50 grams of the metal occupies a volume of

Chemistry

1 answer:

Svetach [21]3 years ago

8 0

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

volume of Osmium metal = 2.22 cm³

mass = 50 g

It's density is

$density = \frac{50}{2.22} \\ = 22.522522522...$

We have the final answer as

Hope this helps you

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Create the Equation: What is the Percent Yield of Ammonia (NH3) if 11.8 g is recovered in a reaction with 7.02 x 10^23 molecules

insens350 [35]

Answer:

Explanation:

The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a

100

yield.

The balanced chemical equation

(

)

(

)

→

(

)

tells you that every

mole of nitrogen gas that takes part in the reaction will consume

moles of hydrogen gas and produce

mole of ammonia.

In your case, you know that

mole of nitrogen gas reacts with

mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react

what you need

3 moles H (sub 2)

what you have

1 mole H (sub2)

you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.

So, the reaction will consume

mole of hydrogen gas and produce

mole H

⋅

2 moles NH

moles H

0.667 moles NH

100

yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced

0.50

moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every

100

moles of ammonia that could theoretically be produced.

You know that

0.667

moles will produce

0.50

moles, so you can say that

100

moles NH

in theory

⋅

0.50 moles NH

actual

0.667

moles NH

in theory

75 moles NH

actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

−−−−−−−−−−−−−

or 75 moles NH sub3

I'll leave the answer rounded to two sig figs.

5 0

3 years ago

A solution of 0.0470 M HCl is used to titrate 26.0 mL of an ammonia solution of unknown concentration. The equivalence point is

DanielleElmas [232]

The pH at equivalence point is 12.46

At equivalence point, number of moles of acid, n equals number of moles of base, n'

So, n = n'

CV = C'V' where

C = concentration of acid (HCl) = 0.0470 M,
V = volume of acid = 16.0 mL,
C' = concentration of base (ammonia solution) and
V' = volume of base = 26.0 mL.

<h3>Concentration of ammonia solution</h3>

Making C' subject of the formula, we have

C' = CV/V'

Substituting the values of the variables into the equation, we have

C' = CV/V'

C' = 0.0470 M × 16.0 mL/26.0 mL

C' = 0.752 MmL/26.0 mL

C' = 0.0289 M

<h3>The concentration of acid at equivalence point</h3>

We know that the ion-product of water Kw is

Kw = [H⁺][OH⁻] = where

[H⁺] = concentration of HCl at equivalence point,
[OH⁻] = C' = concentration of ammonia solution = 0.0289 M and
Kw = 1.01 × 10⁻¹⁴

Making [H⁺] subject of the formula, we have

[H⁺} = Kw/[OH⁻]

[H⁺] = 1.01 × 10⁻¹⁴/0.0289

[H⁺] = 34.95 × 10⁻¹⁴

[H⁺] = 3.495 × 10⁻¹³

<h3>pH at equivalence point</h3>

Since pH = -㏒[H⁺]

pH = -㏒[3.495 × 10⁻¹³]

pH = -㏒[3.495] + (-㏒10⁻¹³)

pH = -㏒[3.495] + [-13(-㏒10)]

pH = 13 - 0.5434

pH = 12.4566

pH ≅ 12.46

So, the pH at equivalence point is 12.46

Learn more about pH at equivalence point here:

brainly.com/question/25487920

3 0

2 years ago

Describe uses of H2S as analytical regent

konstantin123 [22]

Answer:

Hydrogen sulfide is used primarily to produce sulfuric acid and sulfur. It is also used to create a variety of inorganic sulfides used to create pesticides, leather, dyes, and pharmaceuticals. Hydrogen sulfide is used to produce heavy water for nuclear power plants (like CANDU reactors specifically).

Explanation:

Sana Po it's help

8 0

3 years ago

Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor

marishachu [46]

Answer: Fe - O

Explanation:

1) Start by showing the chart information in a more understandable way:

Elements ---------- Electronegativity

aluminum (Al) ----- 1.61

calcium (Ca) ------- 1

carbon (C) ---------- 2.55

chlorine (Cl) -------- 3.16

fluorine (F) --------- 4

hydrogen (H) ------ 2.2

iron (Fe) ------------- 1.83

nitrogen (N) --------- 3.04

oxygen (O) ----------- 3.44

phosphorus (P) ----- 2.19

potassium (K) -------- 0.82

silicon (Si) ------------- 1.9

sulfur (S) --------------- 2.58

2) Find the electronegativity differences for the atoms in each compound:

i) Ca – Cl: 3.16 - 1 = 2.16

ii) Fe – O: 3.44 - 1.83 = 1.61

iii) H – S: 2.58 - 2.2 = 0.38

iii= F – F = 4 - 4 = 0

3) Analysis

i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.

ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.

iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.

Read more on Brainly.com - brainly.com/question/1309389#readmore

8 0

3 years ago

Read 2 more answers

A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific h

nata0808 [166]

Answer:

Specific heat of alloy = 0.2 j/ g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of bold = 25 g

Heat absorbed = 250 J

Initial Temperature = 25°C

Final temperature = 78°C

Specific heat of alloy = ?

Solution:

Change in temperature:

ΔT = 78°C - 25°C

ΔT = 53°C

Now we will put the values in formula.

Q = m.c. ΔT

250 j = 25 g × c ×53°C

250 j = 1325 g.°C × c

250 j / 1325 g.°C = c

c = 0.2 j/ g.°C

8 0

3 years ago