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Lostsunrise [7]
3 years ago
5

How many moles of atoms are in 7.00 g of 13c? express your answer numerically in moles?

Chemistry
2 answers:
seropon [69]3 years ago
5 0

<em>There are </em><u><em>0.538 moles </em></u><em>of ¹³C atoms in the given 7.00 g sample.</em>

<h2>Further Explanation</h2>

This is a simple mole conversion problem.  It requires the molar mass, or the mass of one mole of a substance, of carbon - 13, an isotope of carbon. An isotope is like a different version of a specific atom. In this case, carbon - 13 is a version of a carbon atom that has one more neutron than the normal carbon atom. It is a little heavier than the normal carbon atom because of its extra neutron.

<h3>Converting Mass to Moles</h3>

To convert from grams of sample to moles of sample, the general equation is:

moles \ of \ sample = \frac{given \ mass}{molar \ mass}

To convert 7.00 g of ¹³C, the equation is:

mole \ of \ ^{13}C \ = \frac{7.00 \ g}{13.00 \ \frac{g}{mol}} \\\boxed {mole \ of \ ^{13}C \ = 0.53846 \ mol}

Since there is only 3 significant figures in the given, the final answer must also have 3 significant figures. Therefore,

\boxed {\boxed {mole \ of \ ^{13}C \ = 0.538 \ mol \ or \ 5.38 \times 10^{-1} \ mol}}

This answer is logical since one mole of ¹³C will have a mass of 13.00 g. The given sample (7.00 g) is less than 13.00 g so the mole equivalent of that should be less than one mole.

<h2>Learn More</h2>
  1. mole conversion  brainly.com/question/12980009
  2. stoichiometry brainly.com/question/10513747
<h3 /><h3>Keywords: moles, molar mass</h3>
Nadusha1986 [10]3 years ago
3 0
Molar mass of 13c = 13 grams
number of moles = mass / molar mass
therefore,
number of moles = 7 / 13
To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:
number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms
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Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
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Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

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Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

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Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

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