Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
Two radius of an atom is equal to the diameter. Adding up all the diameter of the atoms, it should be equal to 9.5 mm. Therefore, we simply convert the units to the same units then divide 1.35 A to 9.5 mm. We calculate as follows:
no. of atoms = 0.0095 m / 1.35x10^-9 m = 7037037 atoms
Hope this answers the question. Have a nice day.
Answer: El HEXAHIDRATO DE SULFATO DE NÍQUEL es incompatible con ácidos fuertes, azufre, Ni (NO3) 2, madera y otros combustibles. (NTP, 1992) A temperatura elevada sufre una reacción violenta con aluminio o magnesio en polvo. Cuando se calienta hasta la descomposición emite humos muy tóxicos de óxidos de azufre
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Answer:
C14H30 -----> C7H14 + C2H4 +C5H10
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