Question

What is the midpoint of a segment in the complex plane with endpoints at 6 – 2i and –4 + 6i?

Answer 1

The middle of 6-2i and -4+6i is 1+2i :)

Answer 2

Answer:

Mid point of 6 – 2i and –4 + 6i is 1+2i

A is correct.

Step-by-step explanation:

We are given two complex number and need to find mid point of them

$z_1=a_1+ib_1\text{ and }z_2=a_2+ib_2$

$\text{Mid point z}=\frac{z_1+z_2}{2}$

$z=\frac{a_1+a_2}{2}+i\frac{b_1+b_2}{2}$

where, $z_1=6-2i\text{ and } z_2=-4+6i$

Mid point of 6 – 2i and –4 + 6i

$z=\frac{6-4}{2}+i\frac{-2+6}{2}$

$z=1+2i$

Thus, Mid point of 6 – 2i and –4 + 6i is 1+2i