Question

A pair of parallel plates is charged by a 24-V battery. How much work is required to move a particle with a charge of-3.0uC from the positive to the negative plate?

Answer 1

Answer:

$72\times 10^{-6}$ J

Explanation:

$V$ = Voltage of the battery = Potential difference across the plates of capacitor = 24 Volts

$q$ = Amount of charge being moved from one plate to another = 3 μC = 3 x 10⁻⁶ C

$W$ = amount of work done in moving the charge

Work done is given as

$W = q V$

$W = (3\times 10^{-6})(24)$

$W = 72\times 10^{-6}$ J

Answer 2

Answer:

The work is 7.2x10^-5 VC

Explanation:

To calculate the work it takes to move a positively charged particle to a negative plate equals:

W = -V*(-q)

where

W is the work = ?

V = voltage = 24 V

q = charge = -3 uC = 3x10^-6 C

Replacing values:

W = (-24 V)*(-3x10^-6 C) = 7.2x10^-5 VC