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Crank
3 years ago
10

Name two energy transformations that occur as Adeline pedals her bicycle up a steep hill and then coasts down the other side.

Physics
2 answers:
Juliette [100K]3 years ago
6 0

Potential energy is first transformed into kinetic energy as she pedals, then gravitational as she coasts down the hill.

Mnenie [13.5K]3 years ago
3 0

Question

Name two energy transformations that occur as Adeline pedals her bicycle up a steep hill and then coasts down the other side.

Answer

Potential energy is first transformed into kinetic energy as she pedals, then gravitational as she coasts down the hill.

So it starts as potential engry sence they are staying still but then been they strt moveing by pedleing upnthe hill it turns/or changes in kentic energy sence we are gping up the when i go bake down i don't use as much force or have to push because the gravity is pulling me down thats when it turns into gravitational energy.


Hope this helps :)  

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Suppose that the velocity (in meters per second) of a sky diver falling near the Earth's surface is given by the following expon
Mice21 [21]

Answer:

4.7 s

Explanation:

The complete question is presented in the attached image to this solution.

v(t) = 61 - 61e⁻⁰•²⁶ᵗ

At what time will v(t) = 43 m/s?

We just substitute 43 m/s into the equation for the velocity of the diver and solve for t.

43 = 61 - 61e⁻⁰•²⁶ᵗ

- 61e⁻⁰•²⁶ᵗ = 43 - 61 = -18

e⁻⁰•²⁶ᵗ = (18/61) = 0.2951

In e⁻⁰•²⁶ᵗ = In 0.2951 = -1.2205

-0.26t = -1.2205

t = (1.2205/0.26) = 4.694 s = 4.7 s to the nearest tenth.

Hope this Helps!!!

6 0
3 years ago
Neutron stars consist only of neutrons and have unbelievably high densities. a typical mass and radius for a neutron star might
Tanya [424]
<span>Density is 3.4x10^18 kg/m^3 Dime weighs 1.5x10^12 pounds The definition of density is simply mass per volume. So let's divide the mass of the neutron star by its volume. First, we need to determine the volume. Assuming the neutron star is a sphere, the volume will be 4/3 pi r^3, so 4/3 pi 1.9x10^3 = 4/3 pi 6.859x10^3 m^3 = 2.873x10^10 m^3 Now divide the mass by the volume 9.9x10^28 kg / 2.873x10^10 m^3 = 3.44588x10^18 kg/m^3 Since we only have 2 significant digits in our data, round to 2 significant digits, giving 3.4x10^18 kg/m^3 Now to figure out how much the dime weighs, just multiply by the volume of the dime. 3.4x10^18 kg/m^3 * 2.0x10^-7 m^3 = 6.8x10^11 kg And to convert from kg to lbs, multiply by 2.20462, so 6.8x10^11 kg * 2.20462 lb/kg = 1.5x10^12 lb</span>
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3 years ago
A block of mass 14.9 kg is pulled to the right by an applied force of 39.4 N. If it moves with constant velocity, how much frict
lakkis [162]

The frictional force is 39.4 N

Explanation:

We can solve this problem by applying Newton's 2nd law of motion: in fact, the net force acting on the block is equal to the product between its mass and its acceleration. So we can write

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

Here we know that the box is moving with constant velocity, so its acceleration is zero:

a=0

This means that the net force is also zero:

\sum F=0

The net force on the block is given by the applied force, forward, and the frictional force, backward:

\sum F = F_a-F_f=0

where

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Therefore, solving for F_f,

F_f=F_a=39.4 N

Learn more about friction:

brainly.com/question/6217246

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8 0
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If you mean pattern designs it’s rocky bumpy and you can see the circle patterns

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7 0
3 years ago
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fenix001 [56]
Correct me if I’m wrong but I think it’s A

Explanation:
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3 years ago
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