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Makovka662 [10]
1 year ago
15

The reactive force developed by a jet engine to push an airplane forward is called thrust, and the thrust developed by the engin

e of a boeing 777 is about 85400 lbf. express this thrust in n and kgf.
Physics
1 answer:
finlep [7]1 year ago
3 0

The value of the thrust developed by the engine of a boeing 777 in N and Kgf are ;

i) 376616N

ii) 38430Kgf

<h3>What is force?</h3>

Force is a push or a pull. The reactive force always serve to balance the applied force. We are here asked to convert the  the thrust developed by the engine of a boeing 777 which is about 85400 lbf to the following units;

i) N

ii)kgf

Thus;

1 Ib = 0.45 Kg

1 lbf = 0.45 Kg * 9.8 m/s^2 = 4.41 N

We know that;

1 lbf = 4.41 N

85400 lbf = 85400 lbf. * 4.41 N/1 lbf

= 376616N

Again;

1 lbf = 0.45 Kgf

85400 lbf = 85400 lbf * 0.45 Kgf/1 lbf

= 38430Kgf

Learn more about force:brainly.com/question/13191643

#SPJ1

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3 years ago
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Answer:

I_2 = 0.146 A

Explanation:

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Applying this to the two generators, we have;

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I_1 = V_rms/(2π(f_1)L)

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So,

I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]

Some values will cance out leaving us with;

I_2/I_1 = f_1/f_2

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Plugging in the relevant values ;

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Answer:

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Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

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