What is 320 million in scientific notation?

Mathematics

2 answers:

astraxan [27]3 years ago

8 0

The scientific notation: 3.2 x10^2

BARSIC [14]3 years ago

3 0

3.2 x 10^2 is the correct answer.

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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

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3 years ago

A pyramid has a rectangular base with dimensions of 3 feet by 7 feet. The height of the rectangular pyramid is 6 feet. Water fil

Alja [10]

Answer:

Step-by-step explanation:

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3 years ago

a phone company offers two monthly plan. plan a costs $30 plus an additional $0.14 for each minute of calls. plan b costs $8 plu

Inessa05 [86]

What’s the question

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3 years ago

Given that x < 5, rewrite 5x - |x - 5| without using absolute value signs.

arsen [322]

For $x$ , $x-5$ , therefore $|x-5|=-(x-5)=-x+5$