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2 years ago

Work out the sum of 1 2 , 1 4 and 2 5 . Give your answer as a mixed number in its simplest form.

Mathematics

1 answer:

ollegr [7]2 years ago

7 0

Answer:

Sum of fractions = 1³/₂₀

Step-by-step explanation:

Given fractions;

1/2 , 1/4 and 2/5

Find:

Sum of fractions

Computation:

1/2 + 1/4 + 2/5

Step 1 ;

Taking LCM of denominator

[(1 x 10) + (1 x 5) + (2 x 4)]/ 20

Step 2 :

Using BODMAS rule;

[10 + 5 + 8] / 20

[15 + 8] / 20

23 / 20

Step 3:

By changing simple fraction into mixed fraction

Sum of fractions = 1³/₂₀

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A rectangle has a perimeter of (20x+12y). If one side of the rectangle is (3x-4y), write the expression for the other side

Nady [450]

Answer:

(7x + 10y)

Step-by-step explanation:

To find this add (3x - 4y) to itself to calculate to lengths of the shorter sides.

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3 years ago

HELP PLEASE solve the right triangle

aleksandrvk [35]

Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

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3 years ago

Use the first and last data points to find the slope intercept equation of a trend line.

andriy [413]

Answer:

y = $\frac{16}{3}x-79$

Step-by-step explanation:

From the given table,

Two points are (1, 15) and (7, 47)

If the two points $(x_1,y_1)$ and $(x_2,y_2)$ are lying on a line then slope 'm' of the line will be,

m = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{47-15}{7-1}$

= $\frac{32}{6}$

= $\frac{16}{3}$

Let the equation of a line passing through (h, k) is,

y - h = m(x - k)

If the line passes through (1, 15)

y - 1 = $\frac{16}{3}(x-15)$

y = $\frac{16}{3}x-\frac{16}{3}(15)+1$

y = $\frac{16}{3}x-80+1$

y = $\frac{16}{3}x-79$

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3 years ago