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timama [110]
3 years ago
5

HWEEEPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

P = 105°

QR = 11.6

M = 45°

LN = 8.5

Step-by-step explanation:

when reading the order of what is given LMN = PRQ the order DOES matter

so whe looking at what is being asked....

P will equal whatever its place is in the opposite equation. In this case that is L. This means that P = L. Since L = 105° then so does P.

You can do this with the rest of the letters. What ever letter is in it's place in the opposite equation that is what it equals.

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PLEASE HELP
postnew [5]

Answer:

Below

Step-by-step explanation:

Substituting the given values:

f(6) = 6(2/3) - 2 =   cube root of 6^2 - 2 = cube root 36 - 2

f(-6)=  (-6)(2/3) - 2 =   cube root of(-6)^2 - 2 = cube root 36 - 2

So This is true,

f(6) =   cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019

2 * f(3) = 2 *  (cube root of 3^2 - 2 )  =  2 * (cube root of 9 - 2) = 0.1602

So False,

4 0
3 years ago
Is 4 m greater or less than 400 dm
vovikov84 [41]
400 dm is greater than 4m... hope this helps
3 0
3 years ago
Read 2 more answers
What is 1556 rounded to the nearest thousand
fgiga [73]
Greetings!

"<span>What is 1556 rounded to the nearest thousand?"...

The thousand place value number is in bold: 1556.

Since the number to the right of the bold number is 5 or greater, we round up.

1556 rounded from the thousand place value is 2000.

Hope this helps.
-Benjamin</span>
6 0
3 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
A container has 200 liters and is losing 6 liters per minute. How many will it have after 10 minutes
IgorLugansk [536]

Answer:

140 liters will remain after 10 mins

Step-by-step explanation:

The easy way is just multiply the amount lost per min by the number of mins.

3 0
3 years ago
Read 2 more answers
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