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masha68 [24]
3 years ago
7

What does each probability mean about the likehood of an event occurring?is the event likely,unlikely,or neither ? A.1 B.1/100 C

.0 D.1/2 E.9/10
Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

A- It means it will always happen, there is no way it won't happen as it is 100%

B- It is very unlikely to happen as it only has a 1 in 100 chance of happening

C- It will never happen, it is impossible as it is 0

D- It will most likely happen as it is 90%

Step-by-step explanation:

A, 1/1 is 100% meaning it will always happen.

B- 1/100 is really low, there is only one chance of an event happening if it was to happen a hundred times.

C- 0/1 means it is impossible to happen as it is o

D- 9/10 is the same as 90/100, which is also equivalent to 90%. This means it is very likely to happen but it will not always happen.

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Find the Perimeter of the figure below, in inches
Andreas93 [3]

Answer:

117.8 in.

Step-by-step explanation:

To find the perimeter, add all the side lengths together. If we do that, we get 117.8 in, which is the answer.

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3 years ago
You believe the population is normally distributed and you know the standard deviation is σ = 6.9 σ = 6.9 . You obtain a sample
kaheart [24]

The critical values is 16

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If f(x) = -7x + 5x2 + 10, what does f(-2) equal?
Iteru [2.4K]

Answer:

44

Step-by-step explanation:

f(x) = -7x + 5x^2 + 10

f(-2) = -7(-2) + 5(-2)^2 + 10

= 14 + 20 + 10

= 44

6 0
3 years ago
I need help with this ASAP!! Please and thank you..
Allushta [10]

Answer:  a) 8%

               b) 34%

               c) 12%

<u>Step-by-step explanation:</u>

a)\quad \dfrac{January\ Clothing}{January\ Payments}=\dfrac{234.75}{2800.00}=0.083\implies \large\boxed{8\%}\\\\\\b)\quad \dfrac{January\ Housing}{January\ Payments}=\dfrac{945.20}{2800.00}=0.337\implies \large\boxed{34\%}\\\\\\c)\quad \dfrac{January\ Transportation}{January\ Payments}=\dfrac{347.46}{2800.00}=0.124\implies \large\boxed{12\%}

8 0
3 years ago
A population of plastic chairs in a factory has a weight's mean of 1.5 kg and a standard deviation of 0.1 kg . Suppose a sample
Firlakuza [10]

Answer:

0.9544 = 95.44% probability that the sample mean will be within +0.02 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 1.5, \sigma = 0.1, n = 100, s = \frac{0.1}{\sqrt{100}} = 0.01

What is the probability that the sample mean will be within +0.02 of the population mean?

Sample mean between 1.5 - 0.02 = 1.48 kg and 1.5 + 0.02 = 1.52 kg, which is the pvalue of Z when X = 1.52 subtracted by the pvalue of Z when X = 1.48. So

X = 1.52

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1.52 - 1.5}{0.01}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 1.48 ​

Z = \frac{X - \mu}{s}

Z = \frac{1.48 - 1.5}{0.01}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +0.02 of the population mean.

3 0
3 years ago
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