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2 years ago

Figure. What are the pairs of congruent angles?

Mathematics

2 answers:

Anna35 [415]2 years ago

7 0

∠QRS and ∠CDE are congruent.

∠RST and ∠DEB are congruent.

∠STQ and ∠EBC are congruent.

∠TQR and ∠BCD are congruent.

You can conclude the above angles are congruent because ∠R and ∠D has the same sign on their angle and so does ∠S and ∠E.

Alexus [3.1K]2 years ago

4 0

Answer:

angle Q,T,C, and B are right (90°)

angle D = R (from the sign)

angle E = S (from the sign)

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Asdasdasd

Amanda [17]

Answer: explanation

Step-by-step explanation:

1. answer:2592

explanation: it says to find the % of the small sample so 45 out of 75 is 60% then says to convert it into a decimal and multiply it by 4,320 which equals 2592.

2. answer:

explanation:540 is 12% of 4500. I don't quite understand what that number is but I'm assuming it's the percentage number and that number is 12 and that's 12% out of 100. if it means what percentage 540 is out of 100 then its 540%

3. answer:30
explanation: 4 out of 20 is 20% converted to decimal is 0.2 then multiply it by 15 0 and that adds to 30.

i hope this helped and i hope its correct

7 0

1 year ago

Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The

guajiro [1.7K]

The given function is,

$y=-5\cos (\frac{\pi}{2}(x-3))+6$

The graph can be drawn as,

The period will be distance between two consequetive maximas,

$\text{Period}=1-(-3)=4$

Thus, period is correct.

The amplitude can be determined as,

$\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}$

Thus, amplitue is incorrect.

The range is,

$y\in\lbrack1,11\rbrack$

Thus, the range is correct.

The midline is,

$\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}$

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0

1 year ago

Solve the equation for a.

Pavel [41]

Answer:

$\large\boxed{a=\dfrac{K}{4+9b}}$

Step-by-step explanation:

$K=4a+9ab\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\K=a(4+9b)\qquad\text{divide both sides by}\ (4+9b)\neq0\\\\\dfrac{K}{(4+9b)}=\dfrac{a(4+9b)}{(4+9b)}\\\\\dfrac{K}{4+9b}=a$