3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
Answer:
1.)
y = 2x + 5 for x = 1
y = 2(1) + 5
y = 2 + 5
y = 7
2.) The function rule that relates the total cost of the party to the number of children n.
TCP = $60 + $4(n)
So basically what you have to do is
