Hello!
So we have (x^2+4)^2+32=12x^2+48 and initial condition of a=x^2+4 and want it rewritten in terms of a and set equal to zero. So we have;
a^2+32=12(x^2+4) so now we have;
a^2+32=12a so now we just get everything on one side to set equal to zero;
a^2 -12a +32=0 is the final answer.
Hope this helps! Any questions please ask! Thank you so much!
X= -2 or X=9
Distribute the x to the (x-9) and then move all the x values to one side and the constants to the other and then solve until you have x by its self. You should get two answers that work.
Answer:
Work out the Area of the figure, then multiply that answer by $25.
Answer:
the one on the right
Step-by-step explanation:
one input cannot have more than one output