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3 years ago

10

A flashlight bulb with a potential difference of 4.5 v across it has a resistance of 8 ohms how much current is the bulb filamen

t

2 answers:

pishuonlain [190]3 years ago

5 0

Current = Voltage / Resistance
= 4.5V / 8= 0.5625A

Nonamiya [84]3 years ago

5 0

Answer:

Current = 0.5625 A

Explanation:

As we know by Ohm's law that potential difference applied across the conductor and current flows in the conductor is given as

$V = i R$

here we know

$V = 4.5 Volts$

$R = 8 ohm$

now from the equation we know

$4.5 = 8 i$

$i = \frac{4.5}{8}$

$i = 0.5625 A$

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The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC

enyata [817]

Answer:

The y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

Explanation:

<u>Given:</u>

Electric field in the region, $\vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.$
Charge placed into the region, $q = 10.4\ nC = 10.4\times 10^{-9}\ C.$

where, $\hat i,\ \hat j$ are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

$\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.$

Thus, the y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

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3 years ago

Which of the following lists are all renewable resources?

earnstyle [38]

The answer is A.

Hydroelectric, which is usually generating electricity through use of a dam.

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3 years ago

A thin ball shell is shaped like a hollow ball with a radius of 42.8 cm. The material is a conductor with charge 0.8 nC A point

Gala2k [10]

Answer:

The Electric field will be 225.92 N/C

Explanation:

Given :

Radius of the hollow sphere R=42.8 cm
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Magnitude of the point charge $q_2=-5.4\times10^{-9}\ \rm C$

We know that the flux of the electric field through a close surface cab be calculated by using Gauss Law which is

$\int EdA=\dfrac{Q_{in}}{\epsilon_0}\\\\E\times4\pi\times 0.428^2=\dfrac{(0.8-5.4)\times10^{-9}}{\epsilon_0}\\\\E=225.92\ \rm N/C$

Hence the Electric Field is calculated.

The answer founded out by you seems to be correct and very close to the exact answer and the concept you have used in your answer is also correct.

5 0

3 years ago

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring sets the full bunch of banan

olga55 [171]

Answer:

Mass of banana is $1.12$ Kg

Explanation:

Step 1: Determine the equation of speed of an object moving in an harmonic motion

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$v = \sqrt{(\frac{k}{m} * A)}$

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Substituting the given values in above equation we get -

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3 years ago

How do you answer number 3 a and b?

netineya [11]

I would assume you answer them by doing the math required.

7 0

4 years ago