Average speed = (total distance covered) / (time to cover the distance)
Total distance covered = (99km + 80km) = 179 km
Time to cover the distance = 8 hours
Average speed = (179km / 8hours)
Average speed = 22.375 km/hour
Answer:
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Explanation:
Given;
orbital period of 3 years, P = 3 years
To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.
Kepler's third law;
P² = a³
where;
P is the orbital period
a is the orbital semi-major axis
(3)² = a³
9 = a³
a = ![a = \sqrt[3]{9} \\\\a = 2.08 \ years](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B9%7D%20%5C%5C%5C%5Ca%20%3D%202.08%20%5C%20years)
Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Answer:
The answer is D.
Explanation:
The Law of Conservation of mass states that matter is not created nor destroyed in a chemical reaction.