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taurus [48]
3 years ago
11

What colour would a bunch of green grapes be in red light? Why?

Physics
1 answer:
Temka [501]3 years ago
7 0

Answer:

they'll be black, because green absorbs red.

Explanation:

any color which absorbs red will appear "black", i.e. green, blue, black

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When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the
Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made X_R = X_G, so we need both equations:

For the red car:

X_R=\frac{a_R*t^2}{2}   With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

X_G=Xo + V_G*t   With V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s   and Xo = 200m

Since both positions will be the same:

\frac{a_R*t^2}{2}=Xo+V_G*t   Solving for t:

t1 = -5.8s  and   t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

D = X_R = \frac{a_R*t^2}{2} = 387.28m

3 0
4 years ago
Look at the diagram showing resistance and flow of electrons.
poizon [28]

The answer would be:

D.

X: Low potential energy

Y: High Potential energy

Z: Flow of electrons

Z is clearly the flow of electrons, as shown by the arrow demonstrating the direction of the flow. So you can easily cross out choices B and C. Now, you can see that Y has more energy stored and X has a lot less, so you can conclude that Y has high potential energy while X has low potential energy.


8 0
3 years ago
Read 2 more answers
Definition: The energy transferred by a force to a moving object.
Marysya12 [62]

Answer:

Force applied

Explanation:

An object will remain at its state of rest unless a non zero for act on it

6 0
3 years ago
Convert 1 second in to solar day<br>​
jeka94

1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
3 Days to Seconds = 259200 90 Days to Seconds = 7776000
4 Days to Seconds = 345600 100 Days to Seconds = 8640000
8 0
3 years ago
A compound microscope has an objective lens of focal length 1.40 cm and an eyepiece with a focal length of 2.20 cm. The objectiv
olchik [2.2K]

Answer:

magnification is - 159

objective distance is 3.85 cm

Explanation:

Given data

focal length f1 = 1.40 cm

focal length f2 = 2.20 cm

separated d = 19.6 cm

to find out

angular magnification and How far from the objective

solution

we know magnification formula that is

magnification = ( - L / f1 ) (D/f2)

here D = 25 cm put all value

magnification = ( - 19.6 / 1.40 ) (25/2.20)

magnification = - 159

and

now we apply lens formula

i/f = 1/q + 1/p

p = f2 = 2.20

so

q = f2 p / p -f2

q = 1.4(2.20) / ( 2.2 - 1.4 )

q = 3.85 cm

so objective distance is 3.85 cm

3 0
3 years ago
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