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Bad White [126]
3 years ago
7

The boiling point for liquid nitrogen at atmospheric pressure is 77k. Is the temperature of an open container of liquid nitrogen

higher,lower than, or equal to 77k? Explain.
Physics
1 answer:
algol133 years ago
8 0
Answer:
It would be lower than because, if the boiling point of that element is 77 Kelvin degrees then if it isn’t at boiling point it would automatically be cooler than that. Even if it’s at its original state. The normal temperature of Liquid Nitrogen is really cold -320.8 degrees.

YOU’RE WELCOME
You might be interested in
1. What is the kinetic Energy of a 1500kg object moving at 21 m/s?
Wewaii [24]
The formula for working out kinetic energy is

=122

KE = kinetic energy
m = mass of a body
v = velocity of a body


kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

For the first one I think :
Answer:
KE = 330750 J

I’m not sure about the second one- sorry

The third is
Answer:
KE = 41454 J

Hope it helps and it is correct, sorry if it isn’t !
8 0
3 years ago
I am a bit confused about this question.
gavmur [86]

How do you know when something is moving ?  You ALWAYS have to compare it to something else.  If the object in question changes its distance or direction from your house, or from your big toe, or from a stake in the ground in your front yard, then you say it's moving.  The thing is:  There's ALWAYS something else to compare it to.

I assume you're sitting on the couch now, staring at the TV, or at your computer, or at your phone.  Compared to the couch, or to the tree in your front yard, or to somebody sitting on top of Mt. Everest, or to downtown Jerusalem, you're NOT moving.  Your distance and direction from the reference point isn't changing.

BUT ... what if you compare yourself to somebody sitting at the North pole of the Sun ?  He has to keep turning his eyes to watch you (because the Earth including you is in orbit around the sun).  So your direction from him keeps changing, and 'relative' to him (compared to him), you're definitely moving.

Now let's go a little farther:  

You're sitting in a comfy seat, reading a book that's in your lap.  Maybe you're even getting sleepy.  You're sitting still in the seat, and the book in your lap isn't moving.

SURPRISE !  Your comfy seat is in Row-27 of a passenger jet, and you're flying to Seattle to visit your Grandma.  right now, you're just passing over Casper, Wyoming, and there's somebody down on the ground playing with a telescope.  He looks at your airplane, and HE says that you, the seat you're sitting in, and your book are ALL moving at almost 500 miles an hour.

The difference is:  YOU're comparing your book to the seat in front of you, and YOU say the book is not moving.  The guy with the telescope is comparing the book to the ground he's standing on, and HE says your book is moving west at 500 miles an hour.

You're BOTH correct.  The description of ANY motion always depends on what you're comparing to.  If you're about to ask "What's the REAL motion of the book ?", then I'm sorry.  There's NO SUCH THING as 'REALLY'.  It always depends on what you're comparing to.  Nine people can be watching the same object, and they can have nine different descriptions of its motion, and they're ALL correct.  They're just comparing the object to different things in their own neighborhood, and the nine things are all moving in different ways.

The bottom line:  MOTION IS ALWAYS RELATIVE (to something else).

8 0
3 years ago
Now, using your mass (in kg), and the figures for g (in the table below), you can calculate your weight on other planets.
Licemer1 [7]

Answer:

1) Weight on Mercury

F =W=mg=68.11 \times 3.61 m.s^{-2}

Explanation:

do the same to the rest and use your calculator to find the weight in N.

3 0
3 years ago
Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl
melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar

The boundary layer thickness is equal to:

\delta=\frac{4.91*1}{Re^{0.5} }  =\frac{4.91*1}{246507^{0.5} } =0.0098 ft

The shear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{1}  )(246507)^{0.5} =0.012

b) If the railing edge is 2 ft, the Reynold number is:

Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar

The boundary layer is equal to:

\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft

The sear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{2}  )(493015.6^{0.5} )=0.0082

c) The drag coefficient is equal to:

C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019

The friction drag is equal to:

F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf

7 0
3 years ago
Helo am desperate answer quick will give brainliest
Anika [276]

Answer:

Pitch. The sound an article makes changes relying upon how quick it is vibrating. At the point when an item vibrates rapidly, sharp sounds are heard. Low-pitched sounds come from things that vibrate all the more gradually.

Explanation:

7 0
3 years ago
Read 2 more answers
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