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irinina [24]
4 years ago
15

What is the lateral area of the cylinder? A. 615.85 ft.2 B. 515.01 ft.2 C. 625.25 ft.2 D. 622.04 ft.2

Mathematics
1 answer:
Nuetrik [128]4 years ago
7 0

For this one, you have to use the lateral area formula 2πrh. Since the radius is half the diameter, it is 11. We already have the height being 9 (height is the distance from each base) so we just have to plug in the numbers.

2π(11)(9) then multiply 11 by 9 to get 99.

2π(99) here we have to multiply 2 by 99 which makes 198.

Now we come to 198π. Since none of the answers have π in them, I'm going to assume that π should be used as 3.1415 or so. After we multiply this by 198 we should get 622.017 which is very close to answer D, 622.04.

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sukhopar [10]

Answer:

(x, y) = (-3, -6)

Step-by-step explanation:

The second equation can be used to write an expression for y:

... -5x -21 = y . . . . . . . add y-21 to both sides

This expression can be substituted for y in the first equation:

... 6 = -4x +(-5x -21)

... 27 = -9x . . . . . add 21, collect terms

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... -5(-3) -21 = y = -6

The solution is x = -3, y = -6.

8 0
3 years ago
The sum of the squares of two consecutive even integers is 884. determine the integers.
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Step-by-step explanation:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. The number of customers in a restaurant during the peak hour of each day for a month varied
Gnom [1K]

Step-by-step explanation:

First we must calculate the interquartile range (IQR), using this equation:

IQR = Q_{3} - Q_{1}

Based on the information provided we fill in:

IQR = 58 - 45

IQR = 13

In order to find what the range for the data set is we need to use the Interquartile Rule:

Q_{1}-1.5 × IQR\\

Q_{3}+1.5 × IQR\\

1.5 × 13 = 19.5

Now we plugin in:

45 - 19.5 = 25.5\\

58 + 19.5 = 77.5

Any number below 25.5 is a possible outlier and any number above 77.5 is a possible outlier.  

Answer:

Based on the results of the calculations, 25 could be a possible outlier in the data set.

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3 years ago
Write a number in which the value of the 3 is ten times greater than the value of the 3 in 135, 864
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Answer:

345,456

Step-by-step explanation:

The value of 3 in 135,864 is 30,000.

We want to write a number that is ten times 30,000.

We could write any other number in which the value of 3 is 300,000.

There are infinitely many numbers that we can write.

Some examples are:

345,456

1,315,445

5,354,456

and so on and so forth.

8 0
4 years ago
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