All categories

3 years ago

Write a number in which the value of the 3 is ten times greater than the value of the 3 in 135, 864

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

8 0

Answer:

345,456

Step-by-step explanation:

The value of 3 in 135,864 is 30,000.

We want to write a number that is ten times 30,000.

We could write any other number in which the value of 3 is 300,000.

There are infinitely many numbers that we can write.

Some examples are:

345,456

1,315,445

5,354,456

and so on and so forth.

You might be interested in

Please tell me an example to share about unit rate! ty :)

Kipish [7]

Joshua is traveling in to Europe and needs to exchange some of his money. $1 is worth .85 euros. Find how much Joshua will get with $40.

8 0

3 years ago

The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked

Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=47-1=46$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$525-2.01\frac{75}{\sqrt{47}}=503.01$

$525+2.01\frac{75}{\sqrt{47}}=546.99$

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:

$ME=t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{t_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval is provided, $t_{\alpha/2}=2.01$ from part a, replacing into formula (2) we got:

$n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464$

So the answer for this case would be n=464 rounded up to the nearest integer

8 0

3 years ago

Kevin has three pieces of wood. Board A is 6 inches long, board B is 11 inches long, and board C is 4 inches long. If the full l

Alik [6]

Answer:

b. no, 6 + 4 < 11

Step-by-step explanation:

To form a triangle, longest length should be less than the sum of the two shorter ones.

4 0

3 years ago

In 4 minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt

kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 minutes, a conveyor belt moves 800 pounds of recyclable

aluminum from the delivery truck to a storage area. A smaller belt

moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are used, find how long it takes to move the cans

to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = $\frac{1}{4}$ shifting/min

Rate of Smaller Belt = $\frac{1}{6}$ shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = $\frac{1}{x}$ shifting/min

Now,

$\frac{1}{4}$ + $\frac{1}{6}$ = $\frac{1}{x}$

⇒ $\frac{6 + 4}{24} = \frac{1}{x}$

⇒ $\frac{10}{24} = \frac{1}{x}$

⇒10x = 24

⇒x = $\frac{24}{10}$ = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0

3 years ago

What i thissss pls help

zubka84 [21]

Answer: A

Step-by-step explanation:

5 is in the ones place rather that the tens place.

8 0

3 years ago

Read 2 more answers