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Svetlanka [38]
3 years ago
6

Write a number in which the value of the 3 is ten times greater than the value of the 3 in 135, 864

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

345,456

Step-by-step explanation:

The value of 3 in 135,864 is 30,000.

We want to write a number that is ten times 30,000.

We could write any other number in which the value of 3 is 300,000.

There are infinitely many numbers that we can write.

Some examples are:

345,456

1,315,445

5,354,456

and so on and so forth.

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Please tell me an example to share about unit rate! ty :)
Kipish [7]
Joshua is traveling in to Europe and needs to exchange some of his money. $1 is worth .85 euros. Find how much Joshua will get with $40.
8 0
3 years ago
The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

8 0
3 years ago
Kevin has three pieces of wood. Board A is 6 inches long, board B is 11 inches long, and board C is 4 inches long. If the full l
Alik [6]

Answer:

b. no, 6 + 4 < 11

Step-by-step explanation:

To form a triangle, longest length should be less than the sum of the two shorter ones.

4 0
3 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
3 years ago
What i thissss pls help
zubka84 [21]

Answer: A

Step-by-step explanation:

5 is in the ones place rather that the tens place.

8 0
3 years ago
Read 2 more answers
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