Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Answer: A
Step-by-step explanation:
3x² - 10x + 5 = 0
a = 3 b = -10 c = 5
Δ = b²- 4ac = 100 - 4.3.5 = 40 > 0 => have 2 solutions
=> x =
or x = 
200+10h =200 +10 (5) = 250
50 +20h = 50 + 20 (5) = 150
definitely merry's company