Answer:
g(4) = 23
Step-by-step explanation:
g(x)=5x+3, find g(4)
g(4) = 5(4) + 3
g(4) = 20 + 3
g(4) = 23
Hope that helps!
Answer:
the answer is 1/64
Step-by-step explanation:
have a nice day
Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.
Hilda's deposit of 4520 earned interest for 91-1 = 90 days.
Hilda's deposit of 580 earned interest for 61-10 = 51 days.
Hilda's deposit of 590 earned interest for 61-23 = 38 days.
Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸
... = $4559.175 +582.843 +592.154
... ≈ $5734.17
Deposits total 4520 +580 +590 = 5690, so interest earned is
... $5734.17 -5690.00 = $44.17
Bonus #2) This problem can be worked the same way, except that withdrawals are subtracted from the final balance.
Owner's deposit of $12,300 earned interest for 91 days.
Owner's withdrawal of $3600 reduced the balance for 53 days.
Owner's withdrawal of $1200 reduced the balance for 10 days.
Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰
... = $12,407.795 -3618.342 -1201.151
... ≈ $7588.30
Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30
Answer:
y = 1/2x + 5
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
When 2 lines are parallel, they have the same slope.
Step 1: Define variables
Random point (2, 6)
<em>m</em> = 1/2
y = 1/2x + b
Step 2: Find <em>b</em>
6 = 1/2(2) + b
6 = 1 + b
5 = b
Step 3: Rewrite parallel linear equation
y = 1/2x + 5
Answer:
For a function y = f(x), the range is the set of all the possible values of y.
In the question you wrote:
y = secx - 2
This can be interpreted as:
y = sec(x - 2)
or
y = sec(x) - 2
So let's see each case (these are kinda the same)
If the function is:
y = sec(x - 2)
Firs remember that:
sec(x) = 1/cos(x)
then we can rewrite:
y = 1/cos(x - 2)
notice that the function cos(x) has the range -1 ≤ y ≤ 1
Then for the two extremes we have:
y = 1/1 = 1
y = 1/-1 = -1
Notice that for:
y = 1/cos(x - 2)
y can never be in the range -1 < x < 1
As the denominator cant be larger, in absolute value, than 1.
Then we can conclude that the range is all reals except the interval:
-1 < y < 1
If instead the function was:
y = sec(x) - 2
y = 1/cos(x) - 2
Then with the same reasoning, the range will be the set of all real values except:
-1 - 2 < y < 1 - 2
-3 < y < -1
