<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
</span>
<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
</span>
Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
</span><span>
</span><span>Answer: correct choice is B.
</span>
Answer:
(-2,1),(-1,2),(-3,5/3)
Step-by-step explanation:
Answer:415320
Step-by-step explanation:
Answer:

Step-by-step explanation:
7. 
6. 
5. ![\displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49](https://tex.z-dn.net/?f=%5Cdisplaystyle%201000%5B0%2C85%5D%5E8%20%3D%20272%2C490525%20%E2%89%88%20%5C%24272%2C49)
4. ![\displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]](https://tex.z-dn.net/?f=%5Cdisplaystyle%201000%20%3D%20a%20%5C%5C%20-15%5C%25%20%2B%20100%5C%25%20%3D%201%20-%20r%3B%2085%5C%25%20%3D%201%20-%20r%20%5C%5C%208%5C%3Ayears%20%3D%20time%5C%3A%5Bt%5D)
3. ![\displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%2Ftext%7BWe%20need%20to%20use%20the%20%22Exponential%20Decay%22%20formula%7D%20-%20f%28t%29%20%3D%20a%5B1%20-%20r%5D%5Et%2C%20where%20a%20%3E%200)
2. 
1. 
I am joyous to assist you anytime.
The answer is 38,400
The scale is 1:40 so the side that is 4 in becomes 160 and the side that is 6 in becomes 240
Multiply 160 and 240 and that is the area of the room
Hope this helps