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Andreyy89
4 years ago
11

Daisy received a class assignment for writing statements in first-order logic form. What option should Daisy use to represent th

e sentence “All birds can sing” in first-order logic? (This is a test question on Plato's 'AI" Artificial Intellengence course)
A. ⱯSb
B. bⱯS
C. ⱯbS
D. BⱯs
E. ⱯSB

D.
Engineering
1 answer:
Kay [80]4 years ago
5 0
Choose the one you feel that right
You might be interested in
Engineer Smith, who is licensed in several jurisdictions, recently had his license acted upon by a licensing authority in one of
Nimfa-mama [501]

Answer:

Assuming the infraction in the other jurisdiction is an infraction in Florida, having approximately the same penalty imposed by the FBPE as was imposed in the other jurisdiction

Explanation:

The idea of 8 hours continuation in the options is irrelevant to this case. Rather, Engineer Smith should expect about the same penalty imposition.

3 0
3 years ago
For this assignment, you will write a program to determine the time and date corresponding to an elapsed number of seconds since
Karolina [17]

A Python program should be written to produce output that corresponds to the given hour, minute, second, day of the month, month's name, year, and day of the week's name.

present_year=2016

present_month="January"

present_date="1"

present_day="Friday"

present_hour=0

present_minute=0

present_second=0

input<-from user(seconds)//taking imput from the user using Python program

   total_seconds=input

   //checking with seconds

   if(total_seconds<60)

       present_second+=total_seconds

   else

       total_minutes=total_seconds/60

       remaining_seconds=total_seconds-total_minutes*60

       present_second+=remaining_seconds

   //checking with minutes

   if(total_minutes<60)

       present_minute+=total_minutes

   else

       total_hours=total_minutes/60

       remaining_minutes=total_minutes-total_hours*60

       present_minute+=remaining_minutes

   //checklng with hours

   if(total_hours<24)

       present_hour+=total_hours

   else

       total_days=total_hours/24

       remaining_hours=total_hours-total_days*24

       present_hour+=remaining_hours

   //checking with days

   total_weeks=total_days/7

   remaining_day=total_days-total_weeks*7

   switch(remaining_day)

       case 1:

           present_day="Friday"

       case 2:

           present_day="Saturday"

       case 3:

           present_day="Sundayday"

       case 4:

           present_day="Monday"

       case 5:

           present_day="Tuesday"

       case 6:

           present_day="Wedday"

       case 7:

           present_day="Thursday"

   //checking with years    

   if(total_days>366)

       while(total_days)

           if(present_year%4==0)

               total_days-=366

               present_year+=1

           if(present_year%4!=4)

               total_days-=365

               present_year+=1

           if(present_year%4!=0&&total_days<365)

               break;

           if(present_year%4==0&&total_days<366)

               break;

   //checking with months and date

   if(total_days<=366)

       while(total_days)

           if(present_month="January")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="February"

                   present_date=0

           if(present_month="February")

               present_date++

               total_days--

               if(present_date==28&&present_year%4!=0)

                   present_month="March"

                   present_date=0

               if(present_date==29&&present_year%4==0)

                   present_month="March"

                   present_date=0

           if(present_month="March")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="April"

                   present_date=0        

           if(present_month="April")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="May"

                   present_date=0        

           if(present_month="May")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="June"

                   present_date=0        

           if(present_month="June")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="July"

                   present_date=0    

           if(present_month="July")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="August"

                   present_date=0    

           if(present_month="August")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="September"

                   present_date=0        

           if(present_month="September")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="October"

                   present_date=0    

           if(present_month="October")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="November"

                   present_date=0    

           if(present_month="November")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="December"

                   present_date=0

           if(present_month="December")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="January"

                   present_date=0

//printing present time

print present_hour:present_minute:present_second present_date present_month present_year present_day          

Learn more about Python program here:

brainly.com/question/28691290

#SPJ4          

3 0
2 years ago
An inductor of ????=6.95 H with negligible resistance is placed in series with a ℰ=12.5 V battery, a ????=3.00 Ω resistor, and a
elena-14-01-66 [18.8K]

Answer:

a) I=0 b) 4.17V c) 0.354 A d) 14.5s

Explanation:

a) consider circuit in the attachment

i(t)= E/R (1- e^(-t/RL))

i(0)= 12.5/3×(1-e^(0/RL))

i(0)=0

b) at t⇒∞

i(∞)= 12.5/3× (1- e^(-∞/RL))

    = 4.17V

c) 1/RL= 1/(6.95×3)= 0.0479616

i(1.85) = 12.5/3 × (1- e^(-1.85×0.0479616)

         = 0.354A

d) I/2= I (1- e^(-t/RL))

t= - RL ln0.5

t= - 3×6.95 × (-0.693)

t= 14.5 s

8 0
4 years ago
What financial arguments could you use to justify your proposed
Gnoma [55]

The recommendation to segregate FLTs and the workers are as follows:-1)Reputation of warehouse:- To be in the market the reputation of warehouse should be good,it can only happen when the worker of that warehouse is happy with the management looks after worker external and internal affairs. There should be two pathways one for vehicle and other for walking in which both can’t use vice versa.2)High Profitability:- When there is no incident or accident happens between the FLTs and the workers in the warehouse then off course the worker will be regular at work then there will be high profit .3)Insurance premium:- If there is zero accident happens in the ware house then there will no claim, the company will be in the profit..

7 0
3 years ago
The elementary liquid-phase series reaction
liraira [26]

Answer:

Concentration of A: \frac{C_{A} }{C_{Ao} } =e^{-k_{1}t }

Concentration of B: \frac{C_{B} }{C_{Ao} } =\frac{k_{1} }{k_{2}-k_{1}  } (e^{-k_{1}t } -e^{-k_{2}t } )

Concentration of C: \frac{C_{C} }{C_{Ao} } =1+\frac{k_{1} }{k_{2}-k_{1}  } e^{-k_{2}t } -\frac{k_{2} }{k_{2}-k_{1}  } e^{-k_{1} t}

the image shows the graphs of the three concentrations

Explanation:

We have the reaction:

A ------->k1--------->B------------->k2--------->C

Each reaction:

r_{A} =-k_{1} C_{A} \\r_{B} =k_{1} C_{A} -k_{2} C_{B} \\r_{C} =k_{2} C_{C}

Where Cn is the concentration of each specie (A,B,C)

The mass balance for A:

-\frac{dC_{A} }{dt} =-r_{A} \\-\frac{dC_{A} }{dt}=k_{1} C_{A} \\-\int\limits^y_x {\frac{dC_{A} }{dt} } \,=k_{1} t\\\frac{C_{A} }{C_{Ao} } =e^{-k_{1}t }

Where x=CAo and y=CA

The mass balance for B:

-\frac{dC_{B} }{dt} =-r_{B} \\-\frac{dC_{B} }{dt}=k_{2} C_{B} -k_{1} C_{A} \\\frac{dC_{B} }{dt}+k_{2} C_{B}=k_{1} C_{A}\\\frac{C_{B} }{C_{Ao} } =\frac{k_{1} }{k_{2}-k_{1}  } (e^{-k_{1}t }-ex^{-k_{2}t }  )

The mass balance for C:

\frac{C_{C} }{C_{Ao} } =1-\frac{C_{A} }{C_{Ao} } -\frac{C_{B} }{C_{Ao} } \\\frac{C_{C} }{C_{Ao} }=1+\frac{k_{1} }{k_{2}-k_{1}  } e^{-k_{2} t}-\frac{k_{2} }{k_{2}-k_{1}  }  e^{-k_{1}t }

The maximum concentration of C is:

C_{Cmax} =C_{Ao} (\frac{k_{2} }{k_{1} } )^{\frac{k_{2} }{k_{2}-k_{1}  }}  =1.6(\frac{0.01}{0.4} )^{\frac{0.01}{0.01-0.4} } =1.76mol/dm^{3}

and the maximum time is:

t_{max} =\frac{ln\frac{k_{2} }{k_{1} } }{k_{2}-k_{1}  } =\frac{ln\frac{0.01}{0.4} }{0.01-0.4} =9.4 h

6 0
3 years ago
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